Industrial design windmill
Boeing’s revolutionary microluttice

Blinking sail windmill US Patent
Number: **7780416**

Patent
Number : 8702393 Blinking sail windmill with safety
control

**“BSW Power
Output Calculations”**

**Wind speed
10m/s**

The detailed calculations below will
shed ample light on the most crucial question concerning the BSW; how much
power the BSW will generate. e

Using
the universally accepted and used formula to calculate power output by wind
turbines: e

Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C_{p})e

P = 0.5 × 1.23 × 2RH × V^{3
}x^{ }C_{p} e

Where:
e

P
= Power output

C_{p}
= The efficiency rating assigned to wind turbines e

R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor

In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post.
e

H: In the BSW, , H is the height of the vertical column of the
active frame e e

V^{3 }=
Wind velocity (cubed) in meters per seconds e e

But before I outline the power output
calculations in some detail, and in order to understand and appreciate how
these calculations are achieved, it is absolutely critical to highlight an
important feature of the structure of the BSW’s frame which plays an important
role how power is generated and calculated: e

A BSW may have 3 frames
(or 4 or 5 or 6) designed to spin and block the wind to generate electricity

Think of the BSW frame as
an Excel sheet consisting of multiple *columns.* The columns
will be juxta positioned next to each other; a series of columns, as if they
are stitched together. BSWs of different sizes will have different number of
columns. The larger the BSW the larger number of columns

The frame of a 10m x10m
BSW has 5 columns, each 10m long; a frame of a 20m x 20m has 10 columns, each
20m long, while a 30m x 40m frame will have 20 columns, each 30m long

Just like an Excel Sheet with multiple cells, each column has
multiple number of component units called Double Sided Units. A Double Sided
Units (DSU) is 2m wide and 1m long. Different size BSWs will have different
number of DSUs. For example, a BSW with 10m x 10m frame will have 200 DSU; a
20m x 20m frame will have 800 DSU while a 30m x 40m will have 2400 DSU”
e

Having briefly explained the general
structure of the BSW’s frame which is directly responsible for generating
power, it is crucial to explain an important feature of the frame of the BSW
that has an enormous and direct impact on how much power it generates; a hasty
use of the aforementioned power output formula will give us a low, *Conservative
Power Output* figure. On the other hand, taking into consideration
the unique structure of the BSW’s frame and how the columns are arranged in
series, the same BSW will yield much higher power output figure or the *Actual
Power Output*. For example, we can show
that

A BSW
with 10m x 10m frame can generate 98.4KW or 388.8 KW

A BSW
with 20m x 20m frame can generate 295KW or 2MW

A BSW
with 30m x 40m frame can generate 590KW or
7.6MW

A BSW
with 40m x 60m frame can generate 1.77MW or 24.4MW

A BSW
with 80m x 100m frame can generate 148MW

A BSW
with 5m x 5m frame can generate 22KW

But how can we explain
this huge discrepancy in power output by the same BSW

As you can notice that the
power discrepancy in a BSW with 10m x 10m frame is huge; (**98.4KW** and **388.8
KW**). In using the power output formula to calculate the lower figure (**98.4KW**)
we simply aggregate the power produced by all five columns i.e. we do not
consider each column separately nor do we assign a unique and corresponding
radius (R) to each individual column. Instead we simply use one general figure
as a radius for all columns and apply it to the entire frame despite the
obvious fact that each column has a unique and different radius of its own and
produces its own specific amount of power which is directly corresponding to
its unique radius

In the 2RH section of the
power output calculation formula quoted above we simply use 20m to denote the
radius (R) of the entire frame, although each of the five columns has different
radius of its own which is its distance from the Central Post of the BSW

In light of the above
explanation, now I would like to show you how we can get two sets of different
power output figures to reflect the above-mentioned observation.

To drive the above point
home and make it absolutely crystal clear I shall use three examples to show
you how we can get a low *conservative *figure and
an *actual *high power output figure for the same BSW

**A: So, let us begin with a BSW with 10m x 10m frame. Attached on
20m arm.** e

*Our calculations can show that this BSW can generate either ***98.4KW*** or *388.8
KW*. But how?* e

This frame has 5 columns,
each column is 2m wide and 10m long

Despite the fact that the
frame has 5 columns we shall assume that all 5 columns will have the same
radius of 20m and they will collectively generate only **98.4KW**. We
can simplify the matter even further by assigning letters to the 5 columns, A,
B, C, D and E. All five lettered columns will have the same radius value of
20m.In the *conservative* method we do not calculate the
power generated separately by each individual column. Instead the frame will be
considered as one integral frame with 20m radius and 10m height. Thus

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e e

P = 0.5 x 1.23 x (2 x 20 x
10) x 10^{3
}x 0.4
= **98.4KW** e

Now, let us calculate
the **actual** power generated by the same BSW with 5 columns. The
power output figure will be a lot higher. And the reason is that each of the 5
columns, A, B, C, D and E generate its own unique amount of power corresponding
directly to the value of its radius

Putting in a nutshell as a
general theory: *“All factors (values) of all 5 columns being equal,
the value of their radius will determine the amount of energy they produce; the
bigger the radius the larger the power output”* e

So how do we do
that?
e

Let us remember that each
of the 5 lettered columns has its own specific radius, reflecting its
corresponding distance from the Central Post of the BSW

Remember the Columns are
positioned in series

So, starting from the far
end of the frame and moving towards the Central Post

Column A is 20m away from
the central Post of the BSW i.e. its radius is 20m

Column B is 18m away from
the Central Post of the BSW i.e. its radius is 18m

Column C is 16m away from
the Central Post of the BSW i.e. its radius is 16m

Column D is 14m away from
the Central Post of the BSW i.e. its radius is 14m

Column E is 12m away from
the Central Post of the BSW i.e. its radius is 12m

Now we are in a position
to calculate the power generated by each column, depending on its corresponding
radius

**Actual Power Output**

Power produced by column A
= 0.5
x 1.23 x (2 x 20 x 10 x 10^{3} x 0.4 = 98.4 KW

Power produced by column B = 0.5 x
1.23 x (2 x 18 x 10) x 10^{3} x 0.4 = 88 KW

Power produced by column C = 0.5 x
1.23 x (2 x 16 x 10) x 10^{3} x 0.4 = 77.6 KW

Power produced by column D = 0.5 x
1.23 x (2 x 14 x 10) x 10^{3} x 0.4 = 67.2 KW

Power produced by column E = 0.5 x
1.23 x (2 x 12 x 10) x 10^{3} x 0.4 = 57.6 KW

Total power output = **388.8 KW**

By adding all the power generated by
all 5 columns the *actual* (total) power generated by the
same BSW is **388.8 KW**, four times
the value of the *conservative* figure of 98.4 KW

**B: In our second example
we shall consider a BSW with 20m x 20m frame. Attached on 30m arm.** e

*The calculations below will show that this BSW can generate as
conservative power *295.2KW *or as actual
power ***2041KW
(2MW)** e

By applying the same method we
previously applied on example A, here is a summary of all the critical
information needed to reach the two sets of power output figures, a low *conservative* figure
and a high *actual* figure representing the total power
generated by all columns combined

A BSW with 20m x 20m frame has 10
columns lettered A, B, C, D, E. F, G, H, I and J

Each column is 2m wide and 20m long

Starting from the far end of the
frame and moving toward the Central Post of the BSW, column A is the farthest
from the Central Pole and J is the closest; the radius values of the ten
columns, from column A to column J, are as follow: 30m, 28m, 26m, 24m, 22m,
20m, 18m, 16m, 14m and 12m

**Conservative Power output**

In a conservative power output
calculation, the radius of the arm is 30m and its height 20m

P = 0.5 x 1.23 x (2 x 30 x 20) x 10^{3
}x 0.4
= 295.2KW

**Actual Power Output:** e

In an actual power output calculation,
we shall calculate the power output of each column, a total of 10 columns. And
because each column produces different amount of power corresponding directly
to the value of its radius, we shall calculate all ten power output values, add
them together and reach the actual power produced by a BSW with 20m x 20m
frame: **Attached on 30m arm**

Power produced by column A
= 0.5
x 1.23 x (2 x 30 x 20) x 10^{3} x 0.4 = 295KW e

Power produced by column B = 0.5 x
1.23 x (2 x 28 x 20) x 10^{3} x 0.4 = 275KW

Power produced by column C = 0.5 x
1.23 x (2 x 26 x 20) x 10^{3} x 0.4 = 255KW

Power produced by column D = 0.5 x
1.23 x (2 x 24 x 20) x 10^{3} x 0.4 = 235KW

Power produced by column E = 0.5 x
1.23 x (2 x 22 x 20) x 10^{3} x 0.4 = 216KW

Power produced by column F
= 0.5
x 1.23 x (2 x 20 x 20 x 10^{3} x 0.4 = 196KW

Power produced by column G = 0.5 x
1.23 x (2 x 18 x 20) x 10^{3} x 0.4 = 176KW

Power produced by column H = 0.5 x
1.23 x (2 x 16 x 20) x 10^{3} x 0.4 =
157KW

Power produced by column I = 0.5 x
1.23 x (2 x 14 x 20) x 10^{3} x 0.4 = 137KW

Power produced by column J = 0.5 x
1.23 x (2 x 2 x 20) x 10^{3} x 0.4 = 99KW

**Total Power = 2041KW (2MW)** e

**C: In our third example we
shall consider a BSW with 30m wide x 40m long frame. Attached on 40m arm** e

*Our calculations will show
that as conservative this BSW can generate *785**KW**** ***or as an actual calculation will generate * 7.6MW
e

By applying the same method which
we’ve applied in the previous two examples, here is a summary of all the
critical information needed to reach the two sets of power output figures, a
low *conservative* figure and a high *actual* figure
representing the total power generated by all the columns combined

A BSW with 30m x 40m frame has 15
columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N and O

Each column is 2m wide and 20m long

Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and J is the closest; the radius values of the columns from
column A to column O are as follow: 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m,
24m, 22m, 20m, 18m, 16m, 14m, and 12m

**Conservative Power output:**e

In a **conservative** power
output calculation, the radius of the frame is 40m and height 30m

P = 0.5 x 1.23 x (2 x 40 x 40) x10^{3
}x 0.4
= 785**KW**** **

**Actual Power Output:**e

In an **actual **power
output calculation, however, we shall calculate the power output of each
column, a total of 15 columns. And because each column generates different
amount of power corresponding directly to the value of its radius, we shall
calculate all 15 power output values, add them up and reach the **actual **power
produced by a BSW with 30m wide x 40m long frame: **Attached on 40m arm **

Power produced by column A
= 0.5
x 1.23 x (2 x 40 x 40) x 10^{3} x 0.4 =
785**KW **

Power produced by column B = 0.5 x
1.23 x (2 x 38 x 40) x 10^{3} x 0.4 = 747**KW **

Power produced by column C = 0.5 x
1.23 x (2 x 36 x 40) x 10^{3} x 0.4 = 708**KW **

Power produced by column D = 0.5 x
1.23 x (2 x 34 x 40) x 10^{3} x 0.4 = 668**KW **

Power produced by column E = 0.5 x
1.23 x (2 x 32 x 40) x 10^{3} x 0.4 = 629**KW **

Power produced by column F
= 0.5
x 1.23 x (2 x 30 x 40x 10^{3} x 0.4 = 590**KW **

Power produced by column G = 0.5 x
1.23 x (2 x 28 x 40) x 10^{3} x 0.4 = 550**KW **

Power produced by column H = 0.5 x
1.23 x (2 x 26 x 40) x 10^{3} x 0.4 = 510**KW **

Power produced by column I = 0.5 x
1.23 x (2 x 24 x 40) x 10^{3} x 0.4 = 471**KW **

Power produced by column J = 0.5 x
1.23 x (2 x 22 x 40) x 10^{3} x 0.4 = 432**KW **

Power produced by column K
= 0.5
x 1.23 x (2 x 20 x 40) x 10^{3} x 0.4 = 393**KW **

Power produced by column L = 0.5 x
1.23 x (2 x 18 x 40) x 10^{3} x 0.4 = 354**KW **

Power produced by column M = 0.5 x
1.23 x (2 x 16 x 40) x 10^{3} x 0.4 = 314**KW **

Power produced by column N = 0.5 x
1.23 x (2 x 14 x 40) x 10^{3} x 0.4 = 275**KW **

Power produced by column O = 0.5 x
1.23 x (2 x 12 x 40) x 10^{3} x 0.4 = 235**KW **

**Total Power = 7661KW or 7.6MW**

**D: In our fourth example
we shall consider a BSW with 40m wide x 60m long frame. Attached on 60m arm** e

*Our calculations will show
that as conservative this BSW can generate ***1.77MW*** or as an actual calculation will generate *24.4MW

By applying the same method which
we’ve applied in the previous two examples, here is a summary of all the
critical information needed to reach the two sets of power output figures, a
low *conservative* figure and a high *actual* figure
representing the total power generated by all the columns combined

A BSW with 40m x 60m frame has 20
columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N, O, P, Q, R, S and T

Each column is 2m wide and 20m long

Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and T is the closest; the radius values of the columns from
column A to column T are as follow: 60m, 58m, 56m, 54m, 52m, 50m, 48m, 46m,
44m, 42m, 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m, 24m and 22m

**Conservative Power output:** e

In a **conservative** power
output calculation, the radius of the frame is 60m and height 60m

P = 0.5 x 1.23 x (2 x 60 x 60) x10^{3
}x 0.4
= 1771200**KW =
1.77MW**

**Actual Power Output:**e

In an **actual **power
output calculation, however, we shall calculate the power output of each
column, a total of 20 columns. And because each column generates different
amount of power corresponding directly to the value of its radius, we shall
calculate all 20 power output values, add them up and reach the **actual **power
produced by a BSW **with 40m wide x 60m long
frame. Attached on 60m arm**

Power produced by column A
= 0.5
x 1.23 x (2 x 60 x 60) x 10^{3} x 0.4 = 1.76MW

Power produced by column B = 0.5 x
1.23 x (2 x 58 x 60) x 10^{3} x 0.4 = 1.72MW

Power produced by column C = 0.5 x
1.23 x (2 x 56 x 60) x 10^{3} x 0.4 =
1.68MW

Power produced by column D = 0.5 x
1.23 x (2 x 54 x 60) x 10^{3} x 0.4 =
1.6MW

Power produced by column E = 0.5 x
1.23 x (2 x 52 x 60) x 10^{3} x 0.4 = 1.56MW

Power produced by column F
= 0.5
x 1.23 x (2 x 50 x 60) x 10^{3} x 0.4 = 1.48MW

Power produced by column G = 0.5 x
1.23 x (2 x 48 x 60) x 10^{3} x 0.4 = 1.44MW

Power produced by column H = 0.5 x
1.23 x (2 x 46 x 60) x 10^{3} x 0.4 = 1.36MW

Power produced by column I = 0.5 x
1.23 x (2 x 44 x 60) x 10^{3} x 0.4 = 1.32MW

Power produced by column J = 0.5 x
1.23 x (2 x 42 x 60) x 10^{3} x 0.4 = 1.24MW

Power produced by column K
= 0.5
x 1.23 x (2 x 40 x 60) x 10^{3} x 0.4 = 1.2MW

Power produced by column L = 0.5 x
1.23 x (2 x 38 x 60) x 10^{3} x 0.4 = 1.12MW

Power produced by column M = 0.5 x
1.23 x (2 x 36 x 60) x 10^{3} x 0.4 = 1.08MW

Power produced by column N = 0.5 x
1.23 x (2 x 34 x 60) x 10^{3} x 0.4 = 1.0MW

Power produced by column O = 0.5 x
1.23 x (2 x 32 x 60) x 10^{3} x 0.4 = 0.96MW

Power produced by column P
= 0.5
x 1.23 x (2 x 30 x 60) x 10^{3} x 0.4 = 0.88MW

Power produced by column Q = 0.5 x
1.23 x (2 x 28 x 60) x 10^{3} x 0.4 = 0.84MW

Power produced by column R = 0.5 x
1.23 x (2 x 26 x 60) x 10^{3} x 0.4 = 0.76MW

Power produced by column S= 0.5 x 1.23
x (2 x 24 x 60) x 10^{3} x 0.4 = 0.72MW

Power produced by column T = 0.5 x
1.23 x (2 x 22 x 60) x 10^{3} x 0.4 = 0.64MW

**Total Power = 24.4MW**

**E: In our fifth example we
shall consider a BSW with 80m wide x 100m long frame. Attached on 100m arm**

*Our calculations will show
that this BSW can generate ***148.9MW**

This calculation will be very long and
boring therefore I will use an innovative method to make it very short

I will divide the frame in to two
parts; calculate the power produced by each part then adding them both so we
get the total power generated by 80m by 100m BSW

First part

It starts from the center to the
length of 60m

This part in the forth example (D) it
has the power of **24.4MW** all we have
to do we divide by 60 and multiply by hundred and we will get our exact result

24.4MW ÷ 60 × 100 = 40.6MW

Second part

It starts from 60m to the length of
100m

We will use the power of the first part,
which we just calculated above 40.6MW, which already has a frame length of 100m.

We will divide it by average length of
the arm of first part which is 30m and multiply by the average length of the
arm of the second part which is 80m

40.6MW ÷ 30 x 80 = 108.2MW

Now we add the power generated
by both parts and we will get the power generated by a BSW 80m x 100m
frame **Attached on 100m arm**

Total Power = 108.2MW + 40.6MW = **148.9MW**

GE 12MW wind turbine has a blade107m
long while BSW has 100m long arm

148.9MW ÷ 12MW = 12.4

Therefore 10 BSW wind turbines will be
equivalent to 124 GE wind turbines

GE 12MW wind turbine

**“BSW Power
Output Calculations for 5m by 5m frame”**

Using
the universally accepted and used formula to calculate power output by wind
turbines:e

Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C_{p}) e

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e

Where:
e

P
= Power output

C_{p}
= The efficiency rating assigned to wind turbines e

R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor e

In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post

H: In the BSW, , H is the height of the vertical column of the
active frame e

V^{3 }=
Wind velocity (cubed) in meters per seconds e

**Lets
calculate power generated by BSW for different wind speeds that are 5m/s &
6m/s & 7m/s & 8m/s 9& m/s 10& m/s. where BSW has a frame 5m by
5m & the arm is 5m too **

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p}

P
= 0.5 × 1.23 × 2 x5x5 × 10^{3 }x^{ }0.4 = **12300W**

P
= 0.5 × 1.23 × 2 x5x5 × 5^{3 }x^{ }0.4
= **1537.5W**

P
= 0.5 × 1.23 × 2 x5x5 × 6^{3 }x^{ }0.4
= **2656.8W**

P
= 0.5 × 1.23 × 2 x5x5 × 7^{3 }x^{ }0.4
= **4218.9W**

P
= 0.5 × 1.23 × 2 x5x5 × 8^{3 }x^{ }0.4
= **6297.6W**

P
= 0.5 × 1.23 × 2 x5x5 × 9^{3 }x^{ }0.4
= **8966.7W**

When
we add all the powers generated by BSW in all these different wind speeds that
is 5m/s & 6m/s & 7m/s & 8m/s 9& m/s 10& m/s then we dived
it by 6 then we will have an idea of the average power generated by BSW in real
life wind speeds, where wind speed changes all the time

Total
power of all six wind speeds = **35977.5W**

Average
power when we divided **35977.5W** by 6 = **5996.25W**

From
these two fingers it is clear that the difference between the power 12300W which is the power at wind
speed 10m/s and the average power 5996.25W for 6 types of wind speeds is
%50

So
from now on when we calculate a power for wind speed of 10m/s all we have to do
is divide it by two then we get the power for average power for six wind
speeds

**We
make the swinging window box one meter by one meter. That will make it to us
easy to make and carry and hold by one person and connect the boxes together **

This frame has 5 columns, each column is 1m wide and 5m long

Despite the fact that the frame has 5 columns we shall assume all
5 columns is just one column which has the radius of 5m and they will
collectively generate only **30750W**

By assigning letters to the 5 columns, A, B, C, D and E. All five
lettered columns will be regarded as one column in the* conservative* power
calculation

In the *conservative* method we do not
calculate the power generated separately by each individual column. Instead the
frame will be considered as one integral frame with 5m radius and 5m height

Thus

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e

We
will have

P
= 0.5 × 1.23 × 2 x5x5 × 10^{3 }x^{ }0.4 =
12300 e

Now, let us calculate the **actual** power generated
by the same BSW with 5 columns. The power output figure will be a lot higher.
And the reason is that each of the 5 columns, A, B, C, D and E generate its own
unique amount of power corresponding directly to the value of its radius

Putting it in a nutshell as a general theory: *“All
factors (values) of all 5 columns being equal, the value of their radius will
determine the amount of energy they produce; the bigger the radius the larger
the power output”* e

So how do we do that? e

Let us remember that each of the 5 lettered columns has its own
specific radius, reflecting its corresponding distance from the Central Post of
the BSW

Remember the Columns are positioned in series

So, starting from the far end of the frame and moving towards the
Central Post: e

Column A is 5m away from the central Post of the BSW i.e. its
radius is 5m

Column B is 4m away from the Central Post of the BSW i.e. its
radius is 4m

Column C is 3m away from the Central Post of the BSW i.e. its
radius is 3m

Column D is 2m away from the Central Post of the BSW i.e. its
radius is 2m

Column E is 1m away from the Central Post of the BSW i.e. its
radius is 1m

Now we are in a position to calculate the power generated by each
column, depending on its corresponding radius

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 5 x 10^{3} x
0.4 = 12300W

Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 5) x 10^{3} x 0.4
= 9840W

Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 5) x 10^{3} x 0.4
= 7380W

Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 5) x 10^{3} x 0.4
= 4920W

Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 5) x 10^{3} x 0.4
= 2460W

Total
power output = 36900**W**

By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is 36900**W**

Average
power for six wind speeds= 36900**/2 = ****18450W**

**If we increase the length of the frame from 5m
to 6m the power will be ****44280W**

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 6 x 10^{3} x
0.4 = **14760W **

Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 6) x 10^{3} x 0.4
= **11808W **

Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 6) x 10^{3} x 0.4
= **8856W **

Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 6 x 10^{3} x 0.4
= **5904W **

Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 6) x 10^{3} x 0.4
= **2952W **

Total
power output = **44280W**

By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is **44280W**

Average
power for six wind speeds= **44280/2 = **22140**W**

**If we increase the length of the frame from 6m
to 7m the power will be ****51660W**

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 7 x 10^{3} x
0.4 = **17220W **

Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 7) x 10^{3} x 0.4
= **13776W **

Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 7) x 10^{3} x 0.4
= **10332W **

Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 7 x 10^{3} x 0.4
= **6888W **

Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 7) x 10^{3} x 0.4
= **3444W **

Total
power output = **51660W**

By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is **51660W**

Average
power for six wind speeds= **51660/2 = ****25830W**

If
we add one meter length to the arm of the BSW so we will have a reduce of 6m
but we keep the frame dimensions as it is 5m by 5m, so we will have a gape
between the hub and the frame its length 1m.

So
we will have the result of power of BSW as below

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p}

We
will have

P =
0.5 × 1.23 × 2 x 6 x 7 × 10^{3 } x 0.4
= 20664W

**Actual Power Output**

Power
produced by column A = 0.5 x 1.23 x (2 x 6 x 7 x 10^{3 }x 0.4 = 20664W

Power
produced by column B = 0.5 x 1.23 x (2 x 5 x 7) x 10^{3 } x 0.4 =
17220W

Power
produced by column C = 0.5 x 1.23 x (2 x 4 x 7) x 10^{3 }x 0.4 = 13776W

Power
produced by column D = 0.5 x 1.23 x (2 x 3 x 7 x 10^{3 }x 0.4 = 10332W

Power
produced by column E = 0.5 x 1.23 x (2 x 2 x 7) x 10^{3 }x 0.4 = 6888W

Total
power output = 68880W

Average
power for six wind speeds= **68880/2 = ****34440W**