##
**Blinking
Sail windmill**
**US patents 7780416
& 8702393 **

**Power output
calculation, when the radius of arm 100m, width of frame 80m & length 100m**
**148.9MW**
0nly ten BSW **148.9MW **turbines will be equivalent to **124** GE 12MW turbines

10MW wind
turbine. Can be manufactured by small workshop, Transported by single track,
assembled by unskilled workers, generator at the base, very easy maintenance,
lasts for tens of years, costs %20 only. Built-in Safety mechanism, so it works
in very strong winds, it will generate electricity even in storm fast winds,
while it will start to spin by itself at 2m/s wind speed without the need for
starter motor
BSW
generates power from 2m/s wind speed to storm speed wind speed
It will put an end to the monopoly
of all wind turbine manufacturers like Suzlon, Gamesa, GE, Hitachi, Siemens,
Vestas
It will put complete end to
all wind turbine blade manufacturers like LM wind power
A BSW
with 5m x 5m frame can generate 22KW
e
A BSW
with 10m x 10m frame can generate 388KW
A BSW
with 20m x 20m frame can generate 2MW e
A BSW
with 30m x 40m frame can generate 7.6MW e
A BSW
with 40m x 60m frame can generate 24.4MW e
A BSW
with 80m x 100m frame can generate 148MW e

**US patent: 21MW. First time in
history sail windmill let wind pass through but extract all its energy**

https://www.youtube.com/watch?v=XhY9GxsQ2i0&feature=youtu.be

**Blinking Sail windmill**

**US patents 7780416 & 8702393**

**Power output calculation, when the radius of arm 100m, width of frame 80m & length 100m**

**148.9MW**

0nly ten BSW

**148.9MW**turbines will be equivalent to**124**GE 12MW turbines
10MW wind
turbine. Can be manufactured by small workshop, Transported by single track,
assembled by unskilled workers, generator at the base, very easy maintenance,
lasts for tens of years, costs %20 only. Built-in Safety mechanism, so it works
in very strong winds, it will generate electricity even in storm fast winds,
while it will start to spin by itself at 2m/s wind speed without the need for
starter motor

BSW
generates power from 2m/s wind speed to storm speed wind speed

It will put an end to the monopoly
of all wind turbine manufacturers like Suzlon, Gamesa, GE, Hitachi, Siemens,
Vestas

It will put complete end to
all wind turbine blade manufacturers like LM wind power

A BSW
with 5m x 5m frame can generate 22KW
e

A BSW
with 10m x 10m frame can generate 388KW

A BSW
with 20m x 20m frame can generate 2MW e

A BSW
with 30m x 40m frame can generate 7.6MW e

A BSW
with 40m x 60m frame can generate 24.4MW e

A BSW
with 80m x 100m frame can generate 148MW e

**US patent: 21MW. First time in history sail windmill let wind pass through but extract all its energy**

https://www.youtube.com/watch?v=XhY9GxsQ2i0&feature=youtu.be

https://www.youtube.com/watch?v=XhY9GxsQ2i0&feature=youtu.be

#
Short video

##
Boeing microluttice Makes the most
powerful windmill ENDs oil coal era

Boeing microluttice Makes the most
powerful windmill ENDs oil coal era

#
Long video

#
Boeing’s revolutionary microluttice
lighter than Dandelion

#
US patent 7780416 blinking sail
windmill gentle wind

#
US patent 7780416 blinking sail
windmill fast wind

##

Industrial design windmill
Boeing’s revolutionary microluttice

Blinking sail windmill US Patent
Number: **7780416**

Patent
Number : 8702393 Blinking sail windmill with safety
control

**“BSW Power
Output Calculations”**
**Wind speed
10m/s**
The detailed calculations below will
shed ample light on the most crucial question concerning the BSW; how much
power the BSW will generate. e
Using
the universally accepted and used formula to calculate power output by wind
turbines: e
Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C_{p})e

P = 0.5 × 1.23 × 2RH × V^{3
}x^{ }C_{p} e

Where:
e
P
= Power output
C_{p}
= The efficiency rating assigned to wind turbines e
R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor
In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post.
e

H: In the BSW, , H is the height of the vertical column of the
active frame e e
V^{3 }=
Wind velocity (cubed) in meters per seconds e e

But before I outline the power output
calculations in some detail, and in order to understand and appreciate how
these calculations are achieved, it is absolutely critical to highlight an
important feature of the structure of the BSW’s frame which plays an important
role how power is generated and calculated: e
A BSW may have 3 frames
(or 4 or 5 or 6) designed to spin and block the wind to generate electricity
Think of the BSW frame as
an Excel sheet consisting of multiple *columns.* The columns
will be juxta positioned next to each other; a series of columns, as if they
are stitched together. BSWs of different sizes will have different number of
columns. The larger the BSW the larger number of columns

The frame of a 10m x10m
BSW has 5 columns, each 10m long; a frame of a 20m x 20m has 10 columns, each
20m long, while a 30m x 40m frame will have 20 columns, each 30m long

Just like an Excel Sheet with multiple cells, each column has
multiple number of component units called Double Sided Units. A Double Sided
Units (DSU) is 2m wide and 1m long. Different size BSWs will have different
number of DSUs. For example, a BSW with 10m x 10m frame will have 200 DSU; a
20m x 20m frame will have 800 DSU while a 30m x 40m will have 2400 DSU”
e

Having briefly explained the general
structure of the BSW’s frame which is directly responsible for generating
power, it is crucial to explain an important feature of the frame of the BSW
that has an enormous and direct impact on how much power it generates; a hasty
use of the aforementioned power output formula will give us a low, *Conservative
Power Output* figure. On the other hand, taking into consideration
the unique structure of the BSW’s frame and how the columns are arranged in
series, the same BSW will yield much higher power output figure or the *Actual
Power Output*. For example, we can show
that

A BSW
with 10m x 10m frame can generate 98.4KW or 388.8 KW
A BSW
with 20m x 20m frame can generate 295KW or 2MW
A BSW
with 30m x 40m frame can generate 590KW or
7.6MW
A BSW
with 40m x 60m frame can generate 1.77MW or 24.4MW
A BSW
with 80m x 100m frame can generate 148MW
A BSW
with 5m x 5m frame can generate 22KW

But how can we explain
this huge discrepancy in power output by the same BSW

As you can notice that the
power discrepancy in a BSW with 10m x 10m frame is huge; (**98.4KW** and **388.8
KW**). In using the power output formula to calculate the lower figure (**98.4KW**)
we simply aggregate the power produced by all five columns i.e. we do not
consider each column separately nor do we assign a unique and corresponding
radius (R) to each individual column. Instead we simply use one general figure
as a radius for all columns and apply it to the entire frame despite the
obvious fact that each column has a unique and different radius of its own and
produces its own specific amount of power which is directly corresponding to
its unique radius

In the 2RH section of the
power output calculation formula quoted above we simply use 20m to denote the
radius (R) of the entire frame, although each of the five columns has different
radius of its own which is its distance from the Central Post of the BSW

In light of the above
explanation, now I would like to show you how we can get two sets of different
power output figures to reflect the above-mentioned observation.
To drive the above point
home and make it absolutely crystal clear I shall use three examples to show
you how we can get a low *conservative *figure and
an *actual *high power output figure for the same BSW

**A: So, let us begin with a BSW with 10m x 10m frame. Attached on
20m arm.** e
*Our calculations can show that this BSW can generate either ***98.4KW*** or *388.8
KW*. But how?* e

This frame has 5 columns,
each column is 2m wide and 10m long
Despite the fact that the
frame has 5 columns we shall assume that all 5 columns will have the same
radius of 20m and they will collectively generate only **98.4KW**. We
can simplify the matter even further by assigning letters to the 5 columns, A,
B, C, D and E. All five lettered columns will have the same radius value of
20m.In the *conservative* method we do not calculate the
power generated separately by each individual column. Instead the frame will be
considered as one integral frame with 20m radius and 10m height. Thus

**Conservative Power Output**
P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e e
P = 0.5 x 1.23 x (2 x 20 x
10) x 10^{3
}x 0.4
= **98.4KW** e

Now, let us calculate
the **actual** power generated by the same BSW with 5 columns. The
power output figure will be a lot higher. And the reason is that each of the 5
columns, A, B, C, D and E generate its own unique amount of power corresponding
directly to the value of its radius

Putting in a nutshell as a
general theory: *“All factors (values) of all 5 columns being equal,
the value of their radius will determine the amount of energy they produce; the
bigger the radius the larger the power output”* e

So how do we do
that?
e

Let us remember that each
of the 5 lettered columns has its own specific radius, reflecting its
corresponding distance from the Central Post of the BSW
Remember the Columns are
positioned in series

So, starting from the far
end of the frame and moving towards the Central Post

Column A is 20m away from
the central Post of the BSW i.e. its radius is 20m
Column B is 18m away from
the Central Post of the BSW i.e. its radius is 18m
Column C is 16m away from
the Central Post of the BSW i.e. its radius is 16m
Column D is 14m away from
the Central Post of the BSW i.e. its radius is 14m

Column E is 12m away from
the Central Post of the BSW i.e. its radius is 12m
Now we are in a position
to calculate the power generated by each column, depending on its corresponding
radius

**Actual Power Output**
Power produced by column A
= 0.5
x 1.23 x (2 x 20 x 10 x 10^{3} x 0.4 = 98.4 KW
Power produced by column B = 0.5 x
1.23 x (2 x 18 x 10) x 10^{3} x 0.4 = 88 KW
Power produced by column C = 0.5 x
1.23 x (2 x 16 x 10) x 10^{3} x 0.4 = 77.6 KW
Power produced by column D = 0.5 x
1.23 x (2 x 14 x 10) x 10^{3} x 0.4 = 67.2 KW
Power produced by column E = 0.5 x
1.23 x (2 x 12 x 10) x 10^{3} x 0.4 = 57.6 KW
Total power output = **388.8 KW**

By adding all the power generated by
all 5 columns the *actual* (total) power generated by the
same BSW is **388.8 KW**, four times
the value of the *conservative* figure of 98.4 KW

**B: In our second example
we shall consider a BSW with 20m x 20m frame. Attached on 30m arm.** e
*The calculations below will show that this BSW can generate as
conservative power *295.2KW *or as actual
power ***2041KW
(2MW)** e

By applying the same method we
previously applied on example A, here is a summary of all the critical
information needed to reach the two sets of power output figures, a low *conservative* figure
and a high *actual* figure representing the total power
generated by all columns combined

A BSW with 20m x 20m frame has 10
columns lettered A, B, C, D, E. F, G, H, I and J
Each column is 2m wide and 20m long
Starting from the far end of the
frame and moving toward the Central Post of the BSW, column A is the farthest
from the Central Pole and J is the closest; the radius values of the ten
columns, from column A to column J, are as follow: 30m, 28m, 26m, 24m, 22m,
20m, 18m, 16m, 14m and 12m

**Conservative Power output**
In a conservative power output
calculation, the radius of the arm is 30m and its height 20m
P = 0.5 x 1.23 x (2 x 30 x 20) x 10^{3
}x 0.4
= 295.2KW

**Actual Power Output:** e
In an actual power output calculation,
we shall calculate the power output of each column, a total of 10 columns. And
because each column produces different amount of power corresponding directly
to the value of its radius, we shall calculate all ten power output values, add
them together and reach the actual power produced by a BSW with 20m x 20m
frame: **Attached on 30m arm**

Power produced by column A
= 0.5
x 1.23 x (2 x 30 x 20) x 10^{3} x 0.4 = 295KW e
Power produced by column B = 0.5 x
1.23 x (2 x 28 x 20) x 10^{3} x 0.4 = 275KW
Power produced by column C = 0.5 x
1.23 x (2 x 26 x 20) x 10^{3} x 0.4 = 255KW
Power produced by column D = 0.5 x
1.23 x (2 x 24 x 20) x 10^{3} x 0.4 = 235KW
Power produced by column E = 0.5 x
1.23 x (2 x 22 x 20) x 10^{3} x 0.4 = 216KW
Power produced by column F
= 0.5
x 1.23 x (2 x 20 x 20 x 10^{3} x 0.4 = 196KW
Power produced by column G = 0.5 x
1.23 x (2 x 18 x 20) x 10^{3} x 0.4 = 176KW
Power produced by column H = 0.5 x
1.23 x (2 x 16 x 20) x 10^{3} x 0.4 =
157KW
Power produced by column I = 0.5 x
1.23 x (2 x 14 x 20) x 10^{3} x 0.4 = 137KW
Power produced by column J = 0.5 x
1.23 x (2 x 2 x 20) x 10^{3} x 0.4 = 99KW
**Total Power = 2041KW (2MW)** e

**C: In our third example we
shall consider a BSW with 30m wide x 40m long frame. Attached on 40m arm** e
*Our calculations will show
that as conservative this BSW can generate *785**KW**** ***or as an actual calculation will generate * 7.6MW
e

By applying the same method which
we’ve applied in the previous two examples, here is a summary of all the
critical information needed to reach the two sets of power output figures, a
low *conservative* figure and a high *actual* figure
representing the total power generated by all the columns combined

A BSW with 30m x 40m frame has 15
columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N and O
Each column is 2m wide and 20m long

Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and J is the closest; the radius values of the columns from
column A to column O are as follow: 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m,
24m, 22m, 20m, 18m, 16m, 14m, and 12m

**Conservative Power output:** e
In a **conservative** power
output calculation, the radius of the frame is 40m and height 30m
P = 0.5 x 1.23 x (2 x 40 x 40) x10^{3
}x 0.4
= 785**KW**** **

**Actual Power Output:** e
In an **actual **power
output calculation, however, we shall calculate the power output of each
column, a total of 15 columns. And because each column generates different
amount of power corresponding directly to the value of its radius, we shall
calculate all 15 power output values, add them up and reach the **actual **power
produced by a BSW with 30m wide x 40m long frame: **Attached on 40m arm **

Power produced by column A
= 0.5
x 1.23 x (2 x 40 x 40) x 10^{3} x 0.4 =
785**KW **
Power produced by column B = 0.5 x
1.23 x (2 x 38 x 40) x 10^{3} x 0.4 = 747**KW **
Power produced by column C = 0.5 x
1.23 x (2 x 36 x 40) x 10^{3} x 0.4 = 708**KW **
Power produced by column D = 0.5 x
1.23 x (2 x 34 x 40) x 10^{3} x 0.4 = 668**KW **
Power produced by column E = 0.5 x
1.23 x (2 x 32 x 40) x 10^{3} x 0.4 = 629**KW **
Power produced by column F
= 0.5
x 1.23 x (2 x 30 x 40x 10^{3} x 0.4 = 590**KW **
Power produced by column G = 0.5 x
1.23 x (2 x 28 x 40) x 10^{3} x 0.4 = 550**KW **
Power produced by column H = 0.5 x
1.23 x (2 x 26 x 40) x 10^{3} x 0.4 = 510**KW **
Power produced by column I = 0.5 x
1.23 x (2 x 24 x 40) x 10^{3} x 0.4 = 471**KW **
Power produced by column J = 0.5 x
1.23 x (2 x 22 x 40) x 10^{3} x 0.4 = 432**KW **
Power produced by column K
= 0.5
x 1.23 x (2 x 20 x 40) x 10^{3} x 0.4 = 393**KW **
Power produced by column L = 0.5 x
1.23 x (2 x 18 x 40) x 10^{3} x 0.4 = 354**KW **
Power produced by column M = 0.5 x
1.23 x (2 x 16 x 40) x 10^{3} x 0.4 = 314**KW **
Power produced by column N = 0.5 x
1.23 x (2 x 14 x 40) x 10^{3} x 0.4 = 275**KW **
Power produced by column O = 0.5 x
1.23 x (2 x 12 x 40) x 10^{3} x 0.4 = 235**KW **
**Total Power = 7661KW or 7.6MW**

**D: In our fourth example
we shall consider a BSW with 40m wide x 60m long frame. Attached on 60m arm** e
*Our calculations will show
that as conservative this BSW can generate ***1.77MW*** or as an actual calculation will generate *24.4MW

By applying the same method which
we’ve applied in the previous two examples, here is a summary of all the
critical information needed to reach the two sets of power output figures, a
low *conservative* figure and a high *actual* figure
representing the total power generated by all the columns combined

A BSW with 40m x 60m frame has 20
columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N, O, P, Q, R, S and T
Each column is 2m wide and 20m long
Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and T is the closest; the radius values of the columns from
column A to column T are as follow: 60m, 58m, 56m, 54m, 52m, 50m, 48m, 46m,
44m, 42m, 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m, 24m and 22m

**Conservative Power output:** e
In a **conservative** power
output calculation, the radius of the frame is 60m and height 60m
P = 0.5 x 1.23 x (2 x 60 x 60) x10^{3
}x 0.4
= 1771200**KW =
1.77MW**

**Actual Power Output:** e
In an **actual **power
output calculation, however, we shall calculate the power output of each
column, a total of 20 columns. And because each column generates different
amount of power corresponding directly to the value of its radius, we shall
calculate all 20 power output values, add them up and reach the **actual **power
produced by a BSW **with 40m wide x 60m long
frame. Attached on 60m arm**

Power produced by column A
= 0.5
x 1.23 x (2 x 60 x 60) x 10^{3} x 0.4 = 1.76MW
Power produced by column B = 0.5 x
1.23 x (2 x 58 x 60) x 10^{3} x 0.4 = 1.72MW
Power produced by column C = 0.5 x
1.23 x (2 x 56 x 60) x 10^{3} x 0.4 =
1.68MW
Power produced by column D = 0.5 x
1.23 x (2 x 54 x 60) x 10^{3} x 0.4 =
1.6MW
Power produced by column E = 0.5 x
1.23 x (2 x 52 x 60) x 10^{3} x 0.4 = 1.56MW
Power produced by column F
= 0.5
x 1.23 x (2 x 50 x 60) x 10^{3} x 0.4 = 1.48MW
Power produced by column G = 0.5 x
1.23 x (2 x 48 x 60) x 10^{3} x 0.4 = 1.44MW
Power produced by column H = 0.5 x
1.23 x (2 x 46 x 60) x 10^{3} x 0.4 = 1.36MW
Power produced by column I = 0.5 x
1.23 x (2 x 44 x 60) x 10^{3} x 0.4 = 1.32MW
Power produced by column J = 0.5 x
1.23 x (2 x 42 x 60) x 10^{3} x 0.4 = 1.24MW
Power produced by column K
= 0.5
x 1.23 x (2 x 40 x 60) x 10^{3} x 0.4 = 1.2MW
Power produced by column L = 0.5 x
1.23 x (2 x 38 x 60) x 10^{3} x 0.4 = 1.12MW
Power produced by column M = 0.5 x
1.23 x (2 x 36 x 60) x 10^{3} x 0.4 = 1.08MW
Power produced by column N = 0.5 x
1.23 x (2 x 34 x 60) x 10^{3} x 0.4 = 1.0MW
Power produced by column O = 0.5 x
1.23 x (2 x 32 x 60) x 10^{3} x 0.4 = 0.96MW
Power produced by column P
= 0.5
x 1.23 x (2 x 30 x 60) x 10^{3} x 0.4 = 0.88MW
Power produced by column Q = 0.5 x
1.23 x (2 x 28 x 60) x 10^{3} x 0.4 = 0.84MW
Power produced by column R = 0.5 x
1.23 x (2 x 26 x 60) x 10^{3} x 0.4 = 0.76MW
Power produced by column S= 0.5 x 1.23
x (2 x 24 x 60) x 10^{3} x 0.4 = 0.72MW
Power produced by column T = 0.5 x
1.23 x (2 x 22 x 60) x 10^{3} x 0.4 = 0.64MW
**Total Power = 24.4MW**

**E: In our fifth example we
shall consider a BSW with 80m wide x 100m long frame. Attached on 100m arm**

*Our calculations will show
that this BSW can generate ***148.9MW**

This calculation will be very long and
boring therefore I will use an innovative method to make it very short

I will divide the frame in to two
parts; calculate the power produced by each part then adding them both so we
get the total power generated by 80m by 100m BSW

First part
It starts from the center to the
length of 60m
This part in the forth example (D) it
has the power of **24.4MW** all we have
to do we divide by 60 and multiply by hundred and we will get our exact result

24.4MW ÷ 60 × 100 = 40.6MW

Second part
It starts from 60m to the length of
100m
We will use the power of the first part,
which we just calculated above 40.6MW, which already has a frame length of 100m.
We will divide it by average length of
the arm of first part which is 30m and multiply by the average length of the
arm of the second part which is 80m

40.6MW ÷ 30 x 80 = 108.2MW

Now we add the power generated
by both parts and we will get the power generated by a BSW 80m x 100m
frame **Attached on 100m arm**

Total Power = 108.2MW + 40.6MW = **148.9MW**

GE 12MW wind turbine has a blade107m
long while BSW has 100m long arm
148.9MW ÷ 12MW = 12.4

Therefore 10 BSW wind turbines will be
equivalent to 124 GE wind turbines

GE 12MW wind turbine

**“BSW Power
Output Calculations for 5m by 5m frame”**
Using
the universally accepted and used formula to calculate power output by wind
turbines: e
Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C_{p}) e
P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e

Where:
e
P
= Power output
C_{p}
= The efficiency rating assigned to wind turbines e
R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor e
In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post

H: In the BSW, , H is the height of the vertical column of the
active frame e
V^{3 }=
Wind velocity (cubed) in meters per seconds e

**Lets
calculate power generated by BSW for different wind speeds that are 5m/s &
6m/s & 7m/s & 8m/s 9& m/s 10& m/s. where BSW has a frame 5m by
5m & the arm is 5m too **

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p}

P
= 0.5 × 1.23 × 2 x5x5 × 10^{3 }x^{ }0.4 = **12300W**

P
= 0.5 × 1.23 × 2 x5x5 × 5^{3 }x^{ }0.4
= **1537.5W**
P
= 0.5 × 1.23 × 2 x5x5 × 6^{3 }x^{ }0.4
= **2656.8W**
P
= 0.5 × 1.23 × 2 x5x5 × 7^{3 }x^{ }0.4
= **4218.9W**
P
= 0.5 × 1.23 × 2 x5x5 × 8^{3 }x^{ }0.4
= **6297.6W**
P
= 0.5 × 1.23 × 2 x5x5 × 9^{3 }x^{ }0.4
= **8966.7W**

When
we add all the powers generated by BSW in all these different wind speeds that
is 5m/s & 6m/s & 7m/s & 8m/s 9& m/s 10& m/s then we dived
it by 6 then we will have an idea of the average power generated by BSW in real
life wind speeds, where wind speed changes all the time

Total
power of all six wind speeds = **35977.5W**

Average
power when we divided **35977.5W** by 6 = **5996.25W**

From
these two fingers it is clear that the difference between the power 12300W which is the power at wind
speed 10m/s and the average power 5996.25W for 6 types of wind speeds is
%50
So
from now on when we calculate a power for wind speed of 10m/s all we have to do
is divide it by two then we get the power for average power for six wind
speeds
**We
make the swinging window box one meter by one meter. That will make it to us
easy to make and carry and hold by one person and connect the boxes together **

This frame has 5 columns, each column is 1m wide and 5m long
Despite the fact that the frame has 5 columns we shall assume all
5 columns is just one column which has the radius of 5m and they will
collectively generate only **30750W**
By assigning letters to the 5 columns, A, B, C, D and E. All five
lettered columns will be regarded as one column in the* conservative* power
calculation
In the *conservative* method we do not
calculate the power generated separately by each individual column. Instead the
frame will be considered as one integral frame with 5m radius and 5m height
Thus

**Conservative Power Output**
P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p} e
We
will have
P
= 0.5 × 1.23 × 2 x5x5 × 10^{3 }x^{ }0.4 =
12300 e

Now, let us calculate the **actual** power generated
by the same BSW with 5 columns. The power output figure will be a lot higher.
And the reason is that each of the 5 columns, A, B, C, D and E generate its own
unique amount of power corresponding directly to the value of its radius

Putting it in a nutshell as a general theory: *“All
factors (values) of all 5 columns being equal, the value of their radius will
determine the amount of energy they produce; the bigger the radius the larger
the power output”* e
So how do we do that? e
Let us remember that each of the 5 lettered columns has its own
specific radius, reflecting its corresponding distance from the Central Post of
the BSW
Remember the Columns are positioned in series

So, starting from the far end of the frame and moving towards the
Central Post: e
Column A is 5m away from the central Post of the BSW i.e. its
radius is 5m
Column B is 4m away from the Central Post of the BSW i.e. its
radius is 4m
Column C is 3m away from the Central Post of the BSW i.e. its
radius is 3m
Column D is 2m away from the Central Post of the BSW i.e. its
radius is 2m
Column E is 1m away from the Central Post of the BSW i.e. its
radius is 1m

Now we are in a position to calculate the power generated by each
column, depending on its corresponding radius

**Actual Power Output**
Power produced by column A = 0.5 x 1.23 x (2 x 5 x 5 x 10^{3} x
0.4 = 12300W
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 5) x 10^{3} x 0.4
= 9840W
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 5) x 10^{3} x 0.4
= 7380W
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 5) x 10^{3} x 0.4
= 4920W
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 5) x 10^{3} x 0.4
= 2460W
Total
power output = 36900**W**
By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is 36900**W**
Average
power for six wind speeds= 36900**/2 = ****18450W**

**If we increase the length of the frame from 5m
to 6m the power will be ****44280W**

**Actual Power Output**
Power produced by column A = 0.5 x 1.23 x (2 x 5 x 6 x 10^{3} x
0.4 = **14760W **
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 6) x 10^{3} x 0.4
= **11808W **
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 6) x 10^{3} x 0.4
= **8856W **
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 6 x 10^{3} x 0.4
= **5904W **
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 6) x 10^{3} x 0.4
= **2952W **
Total
power output = **44280W**

By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is **44280W**

Average
power for six wind speeds= **44280/2 = **22140**W**

**If we increase the length of the frame from 6m
to 7m the power will be ****51660W**

**Actual Power Output**
Power produced by column A = 0.5 x 1.23 x (2 x 5 x 7 x 10^{3} x
0.4 = **17220W **
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 7) x 10^{3} x 0.4
= **13776W **
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 7) x 10^{3} x 0.4
= **10332W **
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 7 x 10^{3} x 0.4
= **6888W **
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 7) x 10^{3} x 0.4
= **3444W **
Total
power output = **51660W**

By
adding all the power generated by all 5 columns the *actual* (total)
power generated by the same BSW is **51660W**

Average
power for six wind speeds= **51660/2 = ****25830W**

If
we add one meter length to the arm of the BSW so we will have a reduce of 6m
but we keep the frame dimensions as it is 5m by 5m, so we will have a gape
between the hub and the frame its length 1m.
So
we will have the result of power of BSW as below

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V^{3 }x^{ }C_{p}
We
will have
P =
0.5 × 1.23 × 2 x 6 x 7 × 10^{3 } x 0.4
= 20664W
**Actual Power Output**
Power
produced by column A = 0.5 x 1.23 x (2 x 6 x 7 x 10^{3 }x 0.4 = 20664W
Power
produced by column B = 0.5 x 1.23 x (2 x 5 x 7) x 10^{3 } x 0.4 =
17220W
Power
produced by column C = 0.5 x 1.23 x (2 x 4 x 7) x 10^{3 }x 0.4 = 13776W
Power
produced by column D = 0.5 x 1.23 x (2 x 3 x 7 x 10^{3 }x 0.4 = 10332W
Power
produced by column E = 0.5 x 1.23 x (2 x 2 x 7) x 10^{3 }x 0.4 = 6888W
Total
power output = 68880W

Average
power for six wind speeds= **68880/2 = ****34440W**

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Boeing’s revolutionary microluttice

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control

**“BSW Power Output Calculations”**

**Wind speed 10m/s**

The detailed calculations below will
shed ample light on the most crucial question concerning the BSW; how much
power the BSW will generate. e

Using
the universally accepted and used formula to calculate power output by wind
turbines: e

Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C

_{p})e
P = 0.5 × 1.23 × 2RH × V

^{3 }x^{ }C_{p}e
Where:
e

P
= Power output

C

_{p}= The efficiency rating assigned to wind turbines e
R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor

In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post.
e

H: In the BSW, , H is the height of the vertical column of the active frame e e

H: In the BSW, , H is the height of the vertical column of the active frame e e

V

^{3 }= Wind velocity (cubed) in meters per seconds e e
But before I outline the power output
calculations in some detail, and in order to understand and appreciate how
these calculations are achieved, it is absolutely critical to highlight an
important feature of the structure of the BSW’s frame which plays an important
role how power is generated and calculated: e

A BSW may have 3 frames
(or 4 or 5 or 6) designed to spin and block the wind to generate electricity

Think of the BSW frame as
an Excel sheet consisting of multiple

**The columns will be juxta positioned next to each other; a series of columns, as if they are stitched together. BSWs of different sizes will have different number of columns. The larger the BSW the larger number of columns***columns.*
The frame of a 10m x10m
BSW has 5 columns, each 10m long; a frame of a 20m x 20m has 10 columns, each
20m long, while a 30m x 40m frame will have 20 columns, each 30m long

Just like an Excel Sheet with multiple cells, each column has
multiple number of component units called Double Sided Units. A Double Sided
Units (DSU) is 2m wide and 1m long. Different size BSWs will have different
number of DSUs. For example, a BSW with 10m x 10m frame will have 200 DSU; a
20m x 20m frame will have 800 DSU while a 30m x 40m will have 2400 DSU”
e

Having briefly explained the general
structure of the BSW’s frame which is directly responsible for generating
power, it is crucial to explain an important feature of the frame of the BSW
that has an enormous and direct impact on how much power it generates; a hasty
use of the aforementioned power output formula will give us a low,

**figure. On the other hand, taking into consideration the unique structure of the BSW’s frame and how the columns are arranged in series, the same BSW will yield much higher power output figure or the***Conservative Power Output***. For example, we can show that***Actual Power Output*
A BSW
with 10m x 10m frame can generate 98.4KW or 388.8 KW

A BSW
with 20m x 20m frame can generate 295KW or 2MW

A BSW
with 30m x 40m frame can generate 590KW or
7.6MW

A BSW
with 40m x 60m frame can generate 1.77MW or 24.4MW

A BSW
with 80m x 100m frame can generate 148MW

A BSW
with 5m x 5m frame can generate 22KW

But how can we explain
this huge discrepancy in power output by the same BSW

As you can notice that the
power discrepancy in a BSW with 10m x 10m frame is huge; (

**98.4KW**and**388.8 KW**). In using the power output formula to calculate the lower figure (**98.4KW**) we simply aggregate the power produced by all five columns i.e. we do not consider each column separately nor do we assign a unique and corresponding radius (R) to each individual column. Instead we simply use one general figure as a radius for all columns and apply it to the entire frame despite the obvious fact that each column has a unique and different radius of its own and produces its own specific amount of power which is directly corresponding to its unique radius
In the 2RH section of the
power output calculation formula quoted above we simply use 20m to denote the
radius (R) of the entire frame, although each of the five columns has different
radius of its own which is its distance from the Central Post of the BSW

In light of the above
explanation, now I would like to show you how we can get two sets of different
power output figures to reflect the above-mentioned observation.

To drive the above point
home and make it absolutely crystal clear I shall use three examples to show
you how we can get a low

**figure and an***conservative***high power output figure for the same BSW***actual***A: So, let us begin with a BSW with 10m x 10m frame. Attached on 20m arm.**e

*Our calculations can show that this BSW can generate either***98.4KW**e

*or*388.8 KW*. But how?*This frame has 5 columns, each column is 2m wide and 10m long

Despite the fact that the
frame has 5 columns we shall assume that all 5 columns will have the same
radius of 20m and they will collectively generate only

**98.4KW**. We can simplify the matter even further by assigning letters to the 5 columns, A, B, C, D and E. All five lettered columns will have the same radius value of 20m.In the**method we do not calculate the power generated separately by each individual column. Instead the frame will be considered as one integral frame with 20m radius and 10m height. Thus***conservative*

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V

^{3 }x^{ }C_{p}e e
P = 0.5 x 1.23 x (2 x 20 x
10) x 10

^{3 }x 0.4 =**98.4KW**e
Now, let us calculate
the

**actual**power generated by the same BSW with 5 columns. The power output figure will be a lot higher. And the reason is that each of the 5 columns, A, B, C, D and E generate its own unique amount of power corresponding directly to the value of its radius
Putting in a nutshell as a
general theory:

**e***“All factors (values) of all 5 columns being equal, the value of their radius will determine the amount of energy they produce; the bigger the radius the larger the power output”*
So how do we do
that?
e

Let us remember that each
of the 5 lettered columns has its own specific radius, reflecting its
corresponding distance from the Central Post of the BSW

Remember the Columns are
positioned in series

So, starting from the far
end of the frame and moving towards the Central Post

Column A is 20m away from
the central Post of the BSW i.e. its radius is 20m

Column B is 18m away from
the Central Post of the BSW i.e. its radius is 18m

Column C is 16m away from
the Central Post of the BSW i.e. its radius is 16m

Column D is 14m away from
the Central Post of the BSW i.e. its radius is 14m

Column E is 12m away from
the Central Post of the BSW i.e. its radius is 12m

Now we are in a position
to calculate the power generated by each column, depending on its corresponding
radius

**Actual Power Output**

Power produced by column A
= 0.5
x 1.23 x (2 x 20 x 10 x 10

^{3}x 0.4 = 98.4 KW
Power produced by column B = 0.5 x
1.23 x (2 x 18 x 10) x 10

^{3}x 0.4 = 88 KW
Power produced by column C = 0.5 x
1.23 x (2 x 16 x 10) x 10

^{3}x 0.4 = 77.6 KW
Power produced by column D = 0.5 x
1.23 x (2 x 14 x 10) x 10

^{3}x 0.4 = 67.2 KW
Power produced by column E = 0.5 x
1.23 x (2 x 12 x 10) x 10

^{3}x 0.4 = 57.6 KW
Total power output =

**388.8 KW**
By adding all the power generated by
all 5 columns the

**(total) power generated by the same BSW is***actual***388.8 KW**, four times the value of the**figure of 98.4 KW***conservative***B: In our second example we shall consider a BSW with 20m x 20m frame. Attached on 30m arm.**e

**295.2KW**

*The calculations below will show that this BSW can generate as conservative power*

*or as actual power***2041KW (2MW)**e

By applying the same method we
previously applied on example A, here is a summary of all the critical
information needed to reach the two sets of power output figures, a low

**figure and a high***conservative***figure representing the total power generated by all columns combined***actual*
A BSW with 20m x 20m frame has 10
columns lettered A, B, C, D, E. F, G, H, I and J

Each column is 2m wide and 20m long

Starting from the far end of the
frame and moving toward the Central Post of the BSW, column A is the farthest
from the Central Pole and J is the closest; the radius values of the ten
columns, from column A to column J, are as follow: 30m, 28m, 26m, 24m, 22m,
20m, 18m, 16m, 14m and 12m

**Conservative Power output**

In a conservative power output
calculation, the radius of the arm is 30m and its height 20m

P = 0.5 x 1.23 x (2 x 30 x 20) x 10

^{3 }x 0.4 = 295.2KW**Actual Power Output:**e

In an actual power output calculation,
we shall calculate the power output of each column, a total of 10 columns. And
because each column produces different amount of power corresponding directly
to the value of its radius, we shall calculate all ten power output values, add
them together and reach the actual power produced by a BSW with 20m x 20m
frame:

**Attached on 30m arm**Power produced by column A = 0.5 x 1.23 x (2 x 30 x 20) x 10

^{3}x 0.4 = 295KW e

Power produced by column B = 0.5 x
1.23 x (2 x 28 x 20) x 10

^{3}x 0.4 = 275KW
Power produced by column C = 0.5 x
1.23 x (2 x 26 x 20) x 10

^{3}x 0.4 = 255KW
Power produced by column D = 0.5 x
1.23 x (2 x 24 x 20) x 10

^{3}x 0.4 = 235KW
Power produced by column E = 0.5 x
1.23 x (2 x 22 x 20) x 10

^{3}x 0.4 = 216KW
Power produced by column F
= 0.5
x 1.23 x (2 x 20 x 20 x 10

^{3}x 0.4 = 196KW
Power produced by column G = 0.5 x
1.23 x (2 x 18 x 20) x 10

^{3}x 0.4 = 176KW
Power produced by column H = 0.5 x
1.23 x (2 x 16 x 20) x 10

^{3}x 0.4 = 157KW
Power produced by column I = 0.5 x
1.23 x (2 x 14 x 20) x 10

^{3}x 0.4 = 137KW
Power produced by column J = 0.5 x
1.23 x (2 x 2 x 20) x 10

^{3}x 0.4 = 99KW**Total Power = 2041KW (2MW)**e

**C: In our third example we shall consider a BSW with 30m wide x 40m long frame. Attached on 40m arm**e

**785**

*Our calculations will show that as conservative this BSW can generate***KW**

**e**

*or as an actual calculation will generate*7.6MWBy applying the same method which we’ve applied in the previous two examples, here is a summary of all the critical information needed to reach the two sets of power output figures, a low

**figure and a high**

*conservative***figure representing the total power generated by all the columns combined**

*actual*
A BSW with 30m x 40m frame has 15
columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N and O

Each column is 2m wide and 20m long

Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and J is the closest; the radius values of the columns from
column A to column O are as follow: 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m,
24m, 22m, 20m, 18m, 16m, 14m, and 12m

**Conservative Power output:**

In a

**conservative**power output calculation, the radius of the frame is 40m and height 30m
P = 0.5 x 1.23 x (2 x 40 x 40) x10

^{3 }x 0.4 = 785**KW****Actual Power Output:**

In an

**actual**power output calculation, however, we shall calculate the power output of each column, a total of 15 columns. And because each column generates different amount of power corresponding directly to the value of its radius, we shall calculate all 15 power output values, add them up and reach the**actual**power produced by a BSW with 30m wide x 40m long frame:**Attached on 40m arm**Power produced by column A = 0.5 x 1.23 x (2 x 40 x 40) x 10

^{3}x 0.4 = 785

**KW**

Power produced by column B = 0.5 x
1.23 x (2 x 38 x 40) x 10

^{3}x 0.4 = 747**KW**
Power produced by column C = 0.5 x
1.23 x (2 x 36 x 40) x 10

^{3}x 0.4 = 708**KW**
Power produced by column D = 0.5 x
1.23 x (2 x 34 x 40) x 10

^{3}x 0.4 = 668**KW**
Power produced by column E = 0.5 x
1.23 x (2 x 32 x 40) x 10

^{3}x 0.4 = 629**KW**
Power produced by column F
= 0.5
x 1.23 x (2 x 30 x 40x 10

^{3}x 0.4 = 590**KW**
Power produced by column G = 0.5 x
1.23 x (2 x 28 x 40) x 10

^{3}x 0.4 = 550**KW**
Power produced by column H = 0.5 x
1.23 x (2 x 26 x 40) x 10

^{3}x 0.4 = 510**KW**
Power produced by column I = 0.5 x
1.23 x (2 x 24 x 40) x 10

^{3}x 0.4 = 471**KW**
Power produced by column J = 0.5 x
1.23 x (2 x 22 x 40) x 10

^{3}x 0.4 = 432**KW**
Power produced by column K
= 0.5
x 1.23 x (2 x 20 x 40) x 10

^{3}x 0.4 = 393**KW**
Power produced by column L = 0.5 x
1.23 x (2 x 18 x 40) x 10

^{3}x 0.4 = 354**KW**
Power produced by column M = 0.5 x
1.23 x (2 x 16 x 40) x 10

^{3}x 0.4 = 314**KW**
Power produced by column N = 0.5 x
1.23 x (2 x 14 x 40) x 10

^{3}x 0.4 = 275**KW**
Power produced by column O = 0.5 x
1.23 x (2 x 12 x 40) x 10

^{3}x 0.4 = 235**KW****Total Power = 7661KW or 7.6MW**

**D: In our fourth example we shall consider a BSW with 40m wide x 60m long frame. Attached on 60m arm**e

*Our calculations will show that as conservative this BSW can generate***1.77MW**

*or as an actual calculation will generate*24.4MWBy applying the same method which we’ve applied in the previous two examples, here is a summary of all the critical information needed to reach the two sets of power output figures, a low

**figure and a high**

*conservative***figure representing the total power generated by all the columns combined**

*actual*A BSW with 40m x 60m frame has 20 columns lettered A, B, C, D, E. F, G, H, I, J, K, L, M, N, O, P, Q, R, S and T

Each column is 2m wide and 20m long

Starting from the far end of the frame
and moving toward the Central Post of the BSW, column A is the farthest from
the Central Post and T is the closest; the radius values of the columns from
column A to column T are as follow: 60m, 58m, 56m, 54m, 52m, 50m, 48m, 46m,
44m, 42m, 40m, 38m, 36m, 34m, 32m, 30m, 28m, 26m, 24m and 22m

**Conservative Power output:**e

In a

**conservative**power output calculation, the radius of the frame is 60m and height 60m
P = 0.5 x 1.23 x (2 x 60 x 60) x10

^{3 }x 0.4 = 1771200**KW = 1.77MW****Actual Power Output:**

In an

**actual**power output calculation, however, we shall calculate the power output of each column, a total of 20 columns. And because each column generates different amount of power corresponding directly to the value of its radius, we shall calculate all 20 power output values, add them up and reach the**actual**power produced by a BSW**with 40m wide x 60m long frame. Attached on 60m arm**Power produced by column A = 0.5 x 1.23 x (2 x 60 x 60) x 10

^{3}x 0.4 = 1.76MW

Power produced by column B = 0.5 x
1.23 x (2 x 58 x 60) x 10

^{3}x 0.4 = 1.72MW
Power produced by column C = 0.5 x
1.23 x (2 x 56 x 60) x 10

^{3}x 0.4 = 1.68MW
Power produced by column D = 0.5 x
1.23 x (2 x 54 x 60) x 10

^{3}x 0.4 = 1.6MW
Power produced by column E = 0.5 x
1.23 x (2 x 52 x 60) x 10

^{3}x 0.4 = 1.56MW
Power produced by column F
= 0.5
x 1.23 x (2 x 50 x 60) x 10

^{3}x 0.4 = 1.48MW
Power produced by column G = 0.5 x
1.23 x (2 x 48 x 60) x 10

^{3}x 0.4 = 1.44MW
Power produced by column H = 0.5 x
1.23 x (2 x 46 x 60) x 10

^{3}x 0.4 = 1.36MW
Power produced by column I = 0.5 x
1.23 x (2 x 44 x 60) x 10

^{3}x 0.4 = 1.32MW
Power produced by column J = 0.5 x
1.23 x (2 x 42 x 60) x 10

^{3}x 0.4 = 1.24MW
Power produced by column K
= 0.5
x 1.23 x (2 x 40 x 60) x 10

^{3}x 0.4 = 1.2MW
Power produced by column L = 0.5 x
1.23 x (2 x 38 x 60) x 10

^{3}x 0.4 = 1.12MW
Power produced by column M = 0.5 x
1.23 x (2 x 36 x 60) x 10

^{3}x 0.4 = 1.08MW
Power produced by column N = 0.5 x
1.23 x (2 x 34 x 60) x 10

^{3}x 0.4 = 1.0MW
Power produced by column O = 0.5 x
1.23 x (2 x 32 x 60) x 10

^{3}x 0.4 = 0.96MW
Power produced by column P
= 0.5
x 1.23 x (2 x 30 x 60) x 10

^{3}x 0.4 = 0.88MW
Power produced by column Q = 0.5 x
1.23 x (2 x 28 x 60) x 10

^{3}x 0.4 = 0.84MW
Power produced by column R = 0.5 x
1.23 x (2 x 26 x 60) x 10

^{3}x 0.4 = 0.76MW
Power produced by column S= 0.5 x 1.23
x (2 x 24 x 60) x 10

^{3}x 0.4 = 0.72MW
Power produced by column T = 0.5 x
1.23 x (2 x 22 x 60) x 10

^{3}x 0.4 = 0.64MW**Total Power = 24.4MW**

**E: In our fifth example we shall consider a BSW with 80m wide x 100m long frame. Attached on 100m arm**

*Our calculations will show that this BSW can generate***148.9MW**

This calculation will be very long and
boring therefore I will use an innovative method to make it very short

I will divide the frame in to two
parts; calculate the power produced by each part then adding them both so we
get the total power generated by 80m by 100m BSW

First part

It starts from the center to the
length of 60m

This part in the forth example (D) it
has the power of

**24.4MW**all we have to do we divide by 60 and multiply by hundred and we will get our exact result
24.4MW ÷ 60 × 100 = 40.6MW

Second part

It starts from 60m to the length of
100m

We will use the power of the first part,
which we just calculated above 40.6MW, which already has a frame length of 100m.

We will divide it by average length of
the arm of first part which is 30m and multiply by the average length of the
arm of the second part which is 80m

40.6MW ÷ 30 x 80 = 108.2MW

Now we add the power generated by both parts and we will get the power generated by a BSW 80m x 100m frame

Now we add the power generated by both parts and we will get the power generated by a BSW 80m x 100m frame

**Attached on 100m arm**
Total Power = 108.2MW + 40.6MW =

**148.9MW**
GE 12MW wind turbine has a blade107m
long while BSW has 100m long arm

148.9MW ÷ 12MW = 12.4

Therefore 10 BSW wind turbines will be equivalent to 124 GE wind turbines

GE 12MW wind turbine

**“BSW Power Output Calculations for 5m by 5m frame”**

Using
the universally accepted and used formula to calculate power output by wind
turbines: e

Power
output (P) = 0.5 x air density at sea level (1.23) x swept area x wind
velocity cubed x efficiency (C

_{p}) e
P
= 0.5 × 1.23 × 2RH × V

^{3 }x^{ }C_{p}e
Where:
e

P
= Power output

C

_{p}= The efficiency rating assigned to wind turbines e
R=
In a classic wind turbine, with three horizontally spinning rotors, R is the
radius of the spinning rotor e

In
the case of the BSW, however, R is the radius of the active frame denoting the
distance between the frame’s end column and the BSW’s Central Post

H: In the BSW, , H is the height of the vertical column of the active frame e

H: In the BSW, , H is the height of the vertical column of the active frame e

V

^{3 }= Wind velocity (cubed) in meters per seconds e**Lets calculate power generated by BSW for different wind speeds that are 5m/s & 6m/s & 7m/s & 8m/s 9& m/s 10& m/s. where BSW has a frame 5m by 5m & the arm is 5m too**

P = 0.5 × 1.23 × 2RH × V

^{3 }x

^{ }C

_{p}

P
= 0.5 × 1.23 × 2 x5x5 × 10

^{3 }x^{ }0.4 =**12300W**
P
= 0.5 × 1.23 × 2 x5x5 × 5

^{3 }x^{ }0.4 =**1537.5W**
P
= 0.5 × 1.23 × 2 x5x5 × 6

^{3 }x^{ }0.4 =**2656.8W**
P
= 0.5 × 1.23 × 2 x5x5 × 7

^{3 }x^{ }0.4 =**4218.9W**
P
= 0.5 × 1.23 × 2 x5x5 × 8

^{3 }x^{ }0.4 =**6297.6W**
P
= 0.5 × 1.23 × 2 x5x5 × 9

^{3 }x^{ }0.4 =**8966.7W**
When
we add all the powers generated by BSW in all these different wind speeds that
is 5m/s & 6m/s & 7m/s & 8m/s 9& m/s 10& m/s then we dived
it by 6 then we will have an idea of the average power generated by BSW in real
life wind speeds, where wind speed changes all the time

Total
power of all six wind speeds =

**35977.5W**
Average
power when we divided

**35977.5W**by 6 =**5996.25W**
From
these two fingers it is clear that the difference between the power 12300W which is the power at wind
speed 10m/s and the average power 5996.25W for 6 types of wind speeds is
%50

So
from now on when we calculate a power for wind speed of 10m/s all we have to do
is divide it by two then we get the power for average power for six wind
speeds

**We make the swinging window box one meter by one meter. That will make it to us easy to make and carry and hold by one person and connect the boxes together**

This frame has 5 columns, each column is 1m wide and 5m long

Despite the fact that the frame has 5 columns we shall assume all
5 columns is just one column which has the radius of 5m and they will
collectively generate only

**30750W**
By assigning letters to the 5 columns, A, B, C, D and E. All five
lettered columns will be regarded as one column in the

**power calculation***conservative*
In the

**method we do not calculate the power generated separately by each individual column. Instead the frame will be considered as one integral frame with 5m radius and 5m height***conservative*
Thus

**Conservative Power Output**

P
= 0.5 × 1.23 × 2RH × V

^{3 }x^{ }C_{p}e
We
will have

P
= 0.5 × 1.23 × 2 x5x5 × 10

^{3 }x^{ }0.4 = 12300 e
Now, let us calculate the

**actual**power generated by the same BSW with 5 columns. The power output figure will be a lot higher. And the reason is that each of the 5 columns, A, B, C, D and E generate its own unique amount of power corresponding directly to the value of its radius
Putting it in a nutshell as a general theory:

**e***“All factors (values) of all 5 columns being equal, the value of their radius will determine the amount of energy they produce; the bigger the radius the larger the power output”*
So how do we do that? e

Let us remember that each of the 5 lettered columns has its own
specific radius, reflecting its corresponding distance from the Central Post of
the BSW

Remember the Columns are positioned in series

So, starting from the far end of the frame and moving towards the Central Post: e

Column A is 5m away from the central Post of the BSW i.e. its
radius is 5m

Column B is 4m away from the Central Post of the BSW i.e. its
radius is 4m

Column C is 3m away from the Central Post of the BSW i.e. its
radius is 3m

Column D is 2m away from the Central Post of the BSW i.e. its
radius is 2m

Column E is 1m away from the Central Post of the BSW i.e. its
radius is 1m

Now we are in a position to calculate the power generated by each
column, depending on its corresponding radius

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 5 x 10

^{3}x 0.4 = 12300W
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 5) x 10

^{3}x 0.4 = 9840W
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 5) x 10

^{3}x 0.4 = 7380W
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 5) x 10

^{3}x 0.4 = 4920W
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 5) x 10

^{3}x 0.4 = 2460W
Total
power output = 36900

**W**
By
adding all the power generated by all 5 columns the

**(total) power generated by the same BSW is 36900***actual***W**
Average
power for six wind speeds= 36900

**/2 =****18450W****If we increase the length of the frame from 5m to 6m the power will be**

**44280W**

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 6 x 10

^{3}x 0.4 =**14760W**
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 6) x 10

^{3}x 0.4 =**11808W**
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 6) x 10

^{3}x 0.4 =**8856W**
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 6 x 10

^{3}x 0.4 =**5904W**
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 6) x 10

^{3}x 0.4 =**2952W**
Total
power output =

**44280W**
By
adding all the power generated by all 5 columns the

**(total) power generated by the same BSW is***actual***44280W**
Average
power for six wind speeds=

**44280/2 =**22140**W****If we increase the length of the frame from 6m to 7m the power will be**

**51660W**

**Actual Power Output**

Power produced by column A = 0.5 x 1.23 x (2 x 5 x 7 x 10

^{3}x 0.4 =**17220W**
Power
produced by column B = 0.5 x 1.23 x (2 x 4 x 7) x 10

^{3}x 0.4 =**13776W**
Power
produced by column C = 0.5 x 1.23 x (2 x 3 x 7) x 10

^{3}x 0.4 =**10332W**
Power
produced by column D = 0.5 x 1.23 x (2 x 2 x 7 x 10

^{3}x 0.4 =**6888W**
Power
produced by column E = 0.5 x 1.23 x (2 x 1 x 7) x 10

^{3}x 0.4 =**3444W**
Total
power output =

**51660W**
By
adding all the power generated by all 5 columns the

**(total) power generated by the same BSW is***actual***51660W**
Average
power for six wind speeds=

**51660/2 =****25830W**
If
we add one meter length to the arm of the BSW so we will have a reduce of 6m
but we keep the frame dimensions as it is 5m by 5m, so we will have a gape
between the hub and the frame its length 1m.

So
we will have the result of power of BSW as below

**Conservative Power Output**

P = 0.5 × 1.23 × 2RH × V

^{3 }x

^{ }C

_{p}

We
will have

P =
0.5 × 1.23 × 2 x 6 x 7 × 10

^{3 }x 0.4 = 20664W**Actual Power Output**

Power
produced by column A = 0.5 x 1.23 x (2 x 6 x 7 x 10

^{3 }x 0.4 = 20664W
Power
produced by column B = 0.5 x 1.23 x (2 x 5 x 7) x 10

^{3 }x 0.4 = 17220W
Power
produced by column C = 0.5 x 1.23 x (2 x 4 x 7) x 10

^{3 }x 0.4 = 13776W
Power
produced by column D = 0.5 x 1.23 x (2 x 3 x 7 x 10

^{3 }x 0.4 = 10332W
Power
produced by column E = 0.5 x 1.23 x (2 x 2 x 7) x 10

^{3 }x 0.4 = 6888W
Total
power output = 68880W

Average
power for six wind speeds=

**68880/2 =****34440W**##
Speed
to Pressure Conversion

##
Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Pressure = 0.5 x C x D x V^2
C = Drag coefficient
D = Density of air (kg/m^3) e
V = Speed
of air (m/s) e
Obtain the wind speed value you wish to convert to pressure.
It needs to be in meters per second or the equation will not work.
e
Example: V = 10 m/s

Estimate the drag coefficient based on the shape of the surface of your
object that faces the wind. e

Example: C for one face of a cubic object = 1.05

Pressure
= 0.5 x C x D x V^2 e
Pressure
on the frame when wind speed 10m/s = 0.5 x 1.05 x 1.23 x 10^{2} e
Pressure
= 64.575 N/m2
Surface
area of the active frame = 5m x 5m = 25m2

Pressure
on active frame wind speed 10m/s = 25m2
x 64.575 N/m2 = 1614.375 N/m2

Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Estimate the drag coefficient based on the shape of the surface of your object that faces the wind. e

Example: C for one face of a cubic object = 1.05

Pressure = 0.5 x C x D x V^2

C = Drag coefficient

D = Density of air (kg/m^3) e

V = Speed
of air (m/s) e

Obtain the wind speed value you wish to convert to pressure.
It needs to be in meters per second or the equation will not work.
e

Example: V = 10 m/sEstimate the drag coefficient based on the shape of the surface of your object that faces the wind.

Example: C for one face of a cubic object = 1.05

Pressure
= 0.5 x C x D x V^2 e

Pressure
on the frame when wind speed 10m/s = 0.5 x 1.05 x 1.23 x 10

^{2}e
Pressure
= 64.575 N/m2

Surface
area of the active frame = 5m x 5m = 25m2

Pressure
on active frame wind speed 10m/s = 25m2
x 64.575 N/m2 = 1614.375 N/m2

## Formula for the lift pressure on air plane wing or on wind turbine blade

##
Pressure on active frame wind speed 10m/s = 25m2 x 64.575 N/m2 = 1614.375 N/m2

Formula for the lift pressure on air plane wing or on wind turbine bladee ∆P =
P_{1} - P_{2 = } ^{1}/_{2} ρ
v_{2}^{2} - ^{1}/_{2} ρ
v_{1}^{2} = ^{1}/_{2} ρ
(v_{2}^{2} - v_{1}^{2}) ee

Where

e ∆P is delta pressure, ie the difference
between two pressures e

P_{1}
pressure on the flat side of the blade of the wind turbine (high pressure)
e
P_{2 }pressure on the curved side of the blade of the wind turbine
(low pressure) e
ρ density of the air (1.23)
e
v_{1} speed of the wind on the flat side of the
blade of the wind turbine e e
v_{2}
speed of the wind on the curved side of the blade of the wind turbine e

If we take the blade of wind turbine 5m long and 0.5m wide
as an example when wind speed is 10m/s. the speed on the flat surface will be
10m/s while the speed on the curved surface will be 11.3m/s then we will get: e
e∆ρ =
^{1}/_{2} ρ
(v_{2}^{2} - v_{1}^{2})
e
e∆ρ = 1/2 1.23 (11.32 -
102) e
e∆ρ = 17.02935
N/m2 or pascal e

Surface area of one blade = 5 x 0.5 = 2.5m^{2}
Surface area of three blades = 2.5m^{2} x 3 = 7.5m^{2}
Total pressure on all three blades = 7.5m^{2} x
17.02935 = **128.25N**

We calculated the pressure on the BSW which was: e
Pressure
on active frame wind speed 10m/s = 25m^{2 } x 64.575 N/m^{2} = **1614.375N**

When we divide the total pressure exerted on the active
frame of the BSW by the total pressure exerted on the three blades of 5m wind
turbine we will get this: e

**1614.375N**
/ **128.25N** =
12.5 e

Conclusion: e
BSW wind turbine will produce power 12.5 times more than
three blades of 5m horizontal wind turbine. e

**Her I end all my
calculations necessary to prove the power of BLINKING SAIL WINDMILL**

**Below you will find sites
useful which I used its information’s and another calculations comparing the
BLINKING SAIL WINDMILL with GE 12MW wind turbine**

Pressure on active frame wind speed 10m/s = 25m2 x 64.575 N/m2 = 1614.375 N/m2

Formula for the lift pressure on air plane wing or on wind turbine bladee ∆P = P

Formula for the lift pressure on air plane wing or on wind turbine bladee ∆P = P

_{1}- P_{2 = }^{1}/_{2}ρ v_{2}^{2}-^{1}/_{2}ρ v_{1}^{2}=^{1}/_{2}ρ (v_{2}^{2}- v_{1}^{2}) ee
Where

e ∆P is delta pressure, ie the difference
between two pressures e

P

_{1}pressure on the flat side of the blade of the wind turbine (high pressure) e
P

_{2 }pressure on the curved side of the blade of the wind turbine (low pressure) e
ρ density of the air (1.23)
e

v

_{1}speed of the wind on the flat side of the blade of the wind turbine e e
v

_{2}speed of the wind on the curved side of the blade of the wind turbine e
If we take the blade of wind turbine 5m long and 0.5m wide
as an example when wind speed is 10m/s. the speed on the flat surface will be
10m/s while the speed on the curved surface will be 11.3m/s then we will get: e

e∆ρ =

^{1}/_{2}ρ (v_{2}^{2}- v_{1}^{2}) e
e∆ρ = 1/2 1.23 (11.32 -
102) e

e∆ρ = 17.02935
N/m2 or pascal e

Surface area of one blade = 5 x 0.5 = 2.5m

^{2}
Surface area of three blades = 2.5m

^{2}x 3 = 7.5m^{2}
Total pressure on all three blades = 7.5m

^{2}x 17.02935 =**128.25N**
We calculated the pressure on the BSW which was: e

Pressure
on active frame wind speed 10m/s = 25m

^{2 }x 64.575 N/m^{2}=**1614.375N**
When we divide the total pressure exerted on the active
frame of the BSW by the total pressure exerted on the three blades of 5m wind
turbine we will get this: e

**1614.375N**/

**128.25N**= 12.5 e

Conclusion:

BSW wind turbine will produce power 12.5 times more than
three blades of 5m horizontal wind turbine. e

**Her I end all my calculations necessary to prove the power of BLINKING SAIL WINDMILL**

**Below you will find sites useful which I used its information’s and another calculations comparing the BLINKING SAIL WINDMILL with GE 12MW wind turbine**

##
https://sciencing.com/convert-wind-speed-psi-6003776.html

##
Speed to Pressure Conversion

##
Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ =
"to the power of" e

Obtain the wind speed value you wish to convert to pressure. It needs to be
in meters per second or the equation will not work. e

Example: V = 11 m/s

Estimate the drag coefficient based on the shape of the surface of your
object that faces the wind. e

Example: C for one face of a cubic object = 1.05

Others include: e

Sphere: 0.47 Half-Sphere: 0.42 Cone = 0.5 Corner of a Cube = 0.8 Long
Cylinder = 0.82 Short Cylinder = 1.15 Streamlined body = 0.04 Streamlined
half-body = 0.09

For additional information regarding these shapes, visit the link in the
Resources section. e

Plug the values into the equation and calculate your answer: e

Pressure = 0.5 x 1.05 x 1.25 kg/m^3 x (11 m/s)^2 = 79.4 N/m^2

Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ = "to the power of" e

Obtain the wind speed value you wish to convert to pressure. It needs to be in meters per second or the equation will not work. e

Example: V = 11 m/s

Estimate the drag coefficient based on the shape of the surface of your object that faces the wind. e

Example: C for one face of a cubic object = 1.05

Others include: e

Sphere: 0.47 Half-Sphere: 0.42 Cone = 0.5 Corner of a Cube = 0.8 Long Cylinder = 0.82 Short Cylinder = 1.15 Streamlined body = 0.04 Streamlined half-body = 0.09

For additional information regarding these shapes, visit the link in the Resources section. e

Plug the values into the equation and calculate your answer: e

Pressure = 0.5 x 1.05 x 1.25 kg/m^3 x (11 m/s)^2 = 79.4 N/m^2

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ = "to the power of"

Obtain the wind speed value you wish to convert to pressure. It needs to be in meters per second or the equation will not work.

Example: V = 11 m/s

Estimate the drag coefficient based on the shape of the surface of your object that faces the wind.

Example: C for one face of a cubic object = 1.05

Others include:

Sphere: 0.47 Half-Sphere: 0.42 Cone = 0.5 Corner of a Cube = 0.8 Long Cylinder = 0.82 Short Cylinder = 1.15 Streamlined body = 0.04 Streamlined half-body = 0.09

For additional information regarding these shapes, visit the link in the Resources section.

Plug the values into the equation and calculate your answer:

Pressure = 0.5 x 1.05 x 1.25 kg/m^3 x (11 m/s)^2 = 79.4 N/m^2

##
Unit Conversions

##
Perform any necessary conversions to the units you desire. The wind speed
must be in meters per second for the equation to be accurate.

Convert mph to meters per second (m/s) by multiplying the speed in mph by
0.447. This value is obtained by dividing the number of meters in 1 mile, 1609,
by the number of seconds in 1 hour, 3600. e

Example: 23 mph x 0.447 = 10.3 m/s e
Convert Newton per square meter (N/m^2) to psi by multiplying the pressure
in N/m^2 by 0.000145. This number is based on the number of Newtons in a pound
and the number of square inches in a square meter.

Example: 79.4 N/m^2 x 0.000145 = 0.012 psi

Comparing the blinking sail windmill with GE 12MW wind
turbine

Delta
p = p1 –p2 = 0.5 p v2 seq - 0.5 p v1 seq = 0.5 p (v2 sq – vi sq)
E
∆P
= P_{1} - P_{2 = } ^{1}/_{2} ρ
v_{2}^{2} - ^{1}/_{2} ρ
v_{1}^{2} = ^{1}/_{2} ρ
(v_{2}^{2} - v_{1}^{2})
E
Where

∆P is delta
pressure, ie the difference between two pressures E

P_{1}
pressure on the flat side of the blade of the wind turbine (high pressure)
E
P_{2 }pressure on the curved side of the blade of the wind turbine
(low pressure) E
ρ density of the air (1.23)
E
v_{1} speed of the wind on the flat side of the
blade of the wind turbine E
v_{2}
speed of the wind on the curved side of the blade of the wind turbine E

If we take the blade of GE 107 m long and 4m wide as an
example when wind speed is 10m/s. the wind speed on the flat surface will be
10m/s while the wind speed on the curved surface will be 11.3m/s then we will
get: E
e∆ρ =
^{1}/_{2} ρ
(v_{2}^{2} - v_{1}^{2})
E e
e∆ρ =
^{1}/_{2} 1.23
(11.3^{2} - 10^{2}) E
e∆ρ
= 17.02935 N/m^{2} or **pascal ** e

Surface area of one blade = 107 x 4 = 428m^{2} e
Surface area of three blades = 428m^{2} x 3 = 1284m^{2} e
Total pressure on all three blades = 1284m^{2} x
17.02935 = 21866.52 N/m^{2}
e

BSW has frames 100m by 100m
BSW active surface area of the active frame = 100 x100 =
10000m^{2} e

Perform any necessary conversions to the units you desire. The wind speed
must be in meters per second for the equation to be accurate.

Convert mph to meters per second (m/s) by multiplying the speed in mph by 0.447. This value is obtained by dividing the number of meters in 1 mile, 1609, by the number of seconds in 1 hour, 3600. e

Example: 79.4 N/m^2 x 0.000145 = 0.012 psi

Convert mph to meters per second (m/s) by multiplying the speed in mph by 0.447. This value is obtained by dividing the number of meters in 1 mile, 1609, by the number of seconds in 1 hour, 3600.

Example: 23 mph x 0.447 = 10.3 m/s e

Convert Newton per square meter (N/m^2) to psi by multiplying the pressure
in N/m^2 by 0.000145. This number is based on the number of Newtons in a pound
and the number of square inches in a square meter.Example: 79.4 N/m^2 x 0.000145 = 0.012 psi

Comparing the blinking sail windmill with GE 12MW wind
turbine

Delta
p = p1 –p2 = 0.5 p v2 seq - 0.5 p v1 seq = 0.5 p (v2 sq – vi sq)
E

∆P
= P

_{1}- P_{2 = }^{1}/_{2}ρ v_{2}^{2}-^{1}/_{2}ρ v_{1}^{2}=^{1}/_{2}ρ (v_{2}^{2}- v_{1}^{2}) E
Where

∆P is delta
pressure, ie the difference between two pressures E

P

_{1}pressure on the flat side of the blade of the wind turbine (high pressure) E
P

_{2 }pressure on the curved side of the blade of the wind turbine (low pressure) E
ρ density of the air (1.23)
E

v

_{1}speed of the wind on the flat side of the blade of the wind turbine E
v

_{2}speed of the wind on the curved side of the blade of the wind turbine E
If we take the blade of GE 107 m long and 4m wide as an
example when wind speed is 10m/s. the wind speed on the flat surface will be
10m/s while the wind speed on the curved surface will be 11.3m/s then we will
get: E

e∆ρ =
e

^{1}/_{2}ρ (v_{2}^{2}- v_{1}^{2}) E
e∆ρ =

^{1}/_{2}1.23 (11.3^{2}- 10^{2}) E
e∆ρ
= 17.02935 N/m e

^{2}or**pascal**
Surface area of one blade = 107 x 4 = 428m

^{2}e
Surface area of three blades = 428m

^{2}x 3 = 1284m^{2}e
Total pressure on all three blades = 1284m

^{2}x 17.02935 = 21866.52 N/m^{2}e
BSW has frames 100m by 100m

BSW active surface area of the active frame = 100 x100 =
10000m

^{2}e##
Speed to Pressure Conversion

##
Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ =
"to the power of" E

Obtain
the wind speed value you wish to convert to pressure. It needs to be in meters
per second or the equation will not work.

Example: V = 10 m/s

Estimate the drag coefficient based on the shape of the surface of your
object that faces the wind. E

Example: C for one face of a cubic object = 1.05

Pressure
= 0.5 x C x D x V^2
Pressure
on the frame when wind speed 10m/s =
0.5 x 1.05 x 1.23 x 10^{2}
Pressure
= 64.575 N/m^{2 }

Total pressure on the active frame will be 10000m^{2} x 64.575
N/m^{2 }= 645750N
Total pressure on the active frame = 645750N

When we divide the total pressure exerted on the active
frame of the BSW by the total pressure exerted on the three blades of GE
turbine blades we will get this: e

645750N / 21866.52N
= 29.5

Conclusion: e
BSW wind turbine will produce power 29.5 times more than GE
12MW wind turbine

**Useful sites**

Write this equation converting wind speed in meters per second (m/s) to
pressure in Newton per square meter (N/m^2): e

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ = "to the power of" E

Obtain the wind speed value you wish to convert to pressure. It needs to be in meters per second or the equation will not work.

Example: V = 10 m/s

Estimate the drag coefficient based on the shape of the surface of your object that faces the wind. E

Example: C for one face of a cubic object = 1.05

Pressure = 0.5 x C x D x V^2

C = Drag coefficient D = Density of air (kg/m^3) V = Speed of air (m/s) ^ = "to the power of" E

Obtain the wind speed value you wish to convert to pressure. It needs to be in meters per second or the equation will not work.

Example: V = 10 m/s

Estimate the drag coefficient based on the shape of the surface of your object that faces the wind. E

Example: C for one face of a cubic object = 1.05

Pressure
= 0.5 x C x D x V^2

Pressure
on the frame when wind speed 10m/s =
0.5 x 1.05 x 1.23 x 10

^{2}
Pressure
= 64.575 N/m

^{2 }
Total pressure on the active frame will be 10000m

^{2}x 64.575 N/m^{2 }= 645750N
Total pressure on the active frame = 645750N

When we divide the total pressure exerted on the active
frame of the BSW by the total pressure exerted on the three blades of GE
turbine blades we will get this: e

645750N / 21866.52N
= 29.5

Conclusion: e

BSW wind turbine will produce power 29.5 times more than GE
12MW wind turbine

**Useful sites**

##
Speed to Pressure Conversion

##
https://sciencing.com/convert-wind-speed-psi-6003776.html

##

**How is the pressure
difference created between 2 sides of an airfoil?**

**Lift
Formula**

**Question: GOAL Use
Bernoulli's equation to calculate the lift on an airplane wing PROBLEM An
airplane has w...**

BLINKING
SAIL WINDMILL A to Z

all videos and animations for BSW

kirkuk BSW
prototype plus links to all videos of BSW on youtube

**How is the pressure difference created between 2 sides of an airfoil?**

**Lift Formula**

**Question: GOAL Use Bernoulli's equation to calculate the lift on an airplane wing PROBLEM An airplane has w...**

BLINKING
SAIL WINDMILL A to Z

all videos and animations for BSW

kirkuk BSW
prototype plus links to all videos of BSW on youtube

##
Moving parts and maintenance

The only moving parts in the blinking sail windmill are theswinging windows and the sails.

The swinging windows do not move all the time; they simply swing in high winds only. Since swinging windows are made from metal so they will last for a hundred years. Since they move in just a quarter turn only and in high winds only so their ballbearing will last minimum for hundred years. So the swinging windows will not need maintenance for hundred years.

So we left with the movement of the sails of quarter turn per cycle. The ballbearing will last minimum for 50 years since the ballbearings are currying negligible weight. When we make the sails from long lasting materials like Grafeen or “Carbon Fiber-Reinforced Polymer” or Carbyne, The sail will last for tens of years with no need for maintenance.

So the blinking sail windmill practically shot and forget. Install it and forget the maintenance for 50 years.

Noise

The sails of the BSW won't bang against the green swinging windows, not only because the sails are extremely rigid but also because the spiral springs attached to ball bearing of the sails will prevent the sails from banging against the green swinging windows. They are always a distance of 10cm away from the green swinging windows because when it returns the spiral spring will keep the sail at 10 °degree angle from the vertical plane.

When a powerful wind push the sail it will slowly move until it touches the green swinging window with no noise. When that happens the sail will start to push the green swinging window out of plane to let some of the air pass through. As the wind gets stronger and stronger the gap to let the air pass through will get bigger and bigger; the stronger the wind the larger the gap.

The BSW's built-in safety mechanism is designed so that it can work when wind speed is strong or super strong. The green swinging windows are fitted with spiral Springs. When the wind is weak the green swinging windows are in vertical position but as the wind gets stronger and stronger and the sails start to push the green swinging windows the increased force will push the spiral springs. This will cause the green swinging windows to shift out of plane and consequently permit some of the air to pass freely through the slowly widening gap. As the wind gets stronger the gap will get wider allowing more air to pass through it. The BSW will produce power in slow and fast wind, without making noise.

Birds

the bird can see the Blinking sail windmill clearly since it has wide surface area and its speed is not so fast so no bird deaths will take place like present windmills do since the tip of the blade is moving at 300km per hour and it is invisible due to small surface aria at the tip of the blade.

Helical BSW

Although the animations show “linear” frames, in fact when the BSWs are built and deployed in commercial wind farms their frames will be helical. So, how are the frames arranged and how do they look like as their numbers change?

In a BSW with 4 frames, each frame starts at a point at the bottom on the Central Post and end at the top of the Central Post at 90 degree angle, while in a BSW with three frames, each frame starts at a point at the bottom on the Central Post and end at top of the Central Post at 120 degree angle. Finally, each frame of a BSW with two frames will start at a point at the bottom of the Central Post and end at the top of the Central Post at 180 degrees angle.

Helically-shaped frames are more aerodynamic, evenly spread the torque experienced by the frames as they spin and will prevent pulsations. When the blinking sail windmill becomes helical the columns will spread creating gaps between them, where the wind pushing the sails will have an aerodynamic passageway where wind current move dynamically in the system of blinking sail windmill.

A powerful windmill made from the lightest material in the world manufactured by Boeing a revelatory microluttice lighter than Dandelion.

## Easily assembled and deployable.

## It generates electricity even at extreme low wind.

## The sails of the blinking sail windmill are so light since they are made from microluttice which is lighter than Dandelion. So the lowest wind will blow them away so the wind will pass freely from three frames while the active frame blocks the wind so we have a 20 meter by 20 meter sale blocking the wind and generating huge energy.

## A wind farm made from this blinking sail windmill which cost $100 million it will generate electricity more than a wind farm cost $10 billion made from present windmills.

## The blinking sail windmill will change the landscape of wind energy.

## HRL Researchers Develop World's Lightest Material

## http://www.hrl.com/hrlDocs/pressreleases/2011/prsRls_111117.html

# Boeing: Lightest. Metal. Ever.

## https://www.youtube.com/watch?v=k6N_4jGJADY

## https://www.youtube.com/watch?v=rWEzq8m9KHQ

Industrial design windmill with Boeing’s revolutionary microluttice lighter than Dandelion. Makes the most powerful windmill in history.For Wind farms very low cost easy to assemble by unskilled workers.

https://www.youtube.com/watch?v=yDA0V3L8f0U#t=520

## http://www.youtube.com/watch?v=LNXTm7aHvWc

**My US patents 7780416 & 8702393 windmills the energy it generates is tens of times more than the present windmill for a windmill which costs tenth the cost of the present windmill.**

**Therefore this windmill is hundreds of times more efficient than the present windmill per cost/power generated**

**The blinking sail windmill generates so much electricity due to its large size let’s say the 20 meters by 20 meters that the owner will get his money back in 142 days and that will never happen in any windmill even when they dream of one, the owner of the blinking sail windmill will get his money back in 142 days when he use it to generate electricity or make distilled water in desert countries or when making hydrogen from water to use it in cars instead of using petrol.**

**My windmill has all these three properties it cost 10% only of the cost of the present windmill and this low cost BLINKING SAIL WINDMILL generates ten time more electricity than the present windmill therefore it is 10 x 10 = 100 times more efficient than the present windmill, in view of the cost. Besides that it has much less maintenance cost since the generator is not 170 meters above the ground like the present windmillbecause the blinking sail windmill generator is few meters above the ground .**

therefore no lightening can damage the generator of the blinking sail windmill

.

.

**More energy is used to produce**

**present**wind turbine than it will ever generate**Blinking sail windmill only uses 14.8 tons of steel. All of it can be packed in one single track and assembled by unskilled workers without the use of any crane. It cost %1 of the cost of the present windmill.**

**Building Blinking sail windmill using tower crane**

**We can use present tower crane to make the one megawatt, 1MW blinking sail windmill, simply we fix four arms of the tower crane at the top instead of one. Where we hang on each arm of the tower crane a frame 25m width by 33m height.**

**From the photos below we can see how strong is the tower crane and it can carry the four frames of blinking sail windmill so easily as if it is carrying a father.**

**As we see the crane price can be as low as $22,000 where the four frames will cost less than $15,000**

**So with less than $40,000 we will have a 1MW windmill, if we add the generator price and the foundation cost the entire blinking sail windmill cost will be less than $175,000. With such price the blinking sail windmill will land slide the world of wind power generation.**

Links to tower crane

https://www.youtube.com/watch?v=RB91Sm-kGJ8

The life time of a ballbearing is 500000000 revelations to one million revelation.

The BSW spins between 40-100 rev per minute. Thus, taking the higher figure of turns:

BSW turn/year = 100 x 60 x 24 x 365 = 52,560,000

500000000 ÷ 52560000 = 9.61

The sails of the BSW won't bang against the green swinging windows, not only because the sails are extremely rigid but also because the spiral springs attached to ball bearing will prevent the sails from banging against the green swinging windows. They are always a distance of 10cm away from the green swinging windows because when it returns the spiral spring will keep the sail at 10 °degree angle from the vertical plane.

The BSW's built-in safety mechanism is designed so that it can work in when wind speed is weak or super strong. Thus, a powerful wind will slowly push the sail until it touches the green swinging window so no noise is resulted. When that happens it will start to push the green swinging window out of plane to let some of the air pass through. As the wind gets stronger and stronger the gap to let the air pass through will get bigger and bigger; the stronger the wind the larger the gap.

The green swinging windows too are fitted with spiral Springs. When the wind is weak the green swinging windows are in vertical position but as the wind gets stronger and stronger and the sails start to push the green swinging windows the increased force will push the spiral springs. This will cause the green swinging windows to shift out of plane and consequently permit some of the air to pass freely through the slowly widening gap. As the wind gets stronger the gap will get wider allowing more air to pass through it. The BSW will produce power in slow and fast wind, without making noise.

Given the two salient characteristics of the BSW, massive size and slow motion, it is unfathomable that this turbine will result in killing birds

The life time of a ballbearing is 500000000 revelations to one million revelation.

The BSW spins between 40-100 rev per minute. Thus, taking the higher figure of turns:

BSW turn/year = 100 x 60 x 24 x 365 = 52,560,000

500000000 ÷ 52560000 = 9.61

Since the blinking sail windmill two sail ballbearing is caring very light weight and running at very low speed it will last minimum 20 to 30 years. The same applies to the green swinging window ballbearing.

But Since the sail ballbearing only turns 90 degree only that means quarter turn therefore it will last: years

9.61

x

4

=

38.44 years

9.61

x

4

=

38.44 years

Where the green swinging window only move in strong wind so the ballbearing will last much longer than 38.44 years

Let me now address the concern about noise.The sails of the BSW won't bang against the green swinging windows, not only because the sails are extremely rigid but also because the spiral springs attached to ball bearing will prevent the sails from banging against the green swinging windows. They are always a distance of 10cm away from the green swinging windows because when it returns the spiral spring will keep the sail at 10 °degree angle from the vertical plane.

The BSW's built-in safety mechanism is designed so that it can work in when wind speed is weak or super strong. Thus, a powerful wind will slowly push the sail until it touches the green swinging window so no noise is resulted. When that happens it will start to push the green swinging window out of plane to let some of the air pass through. As the wind gets stronger and stronger the gap to let the air pass through will get bigger and bigger; the stronger the wind the larger the gap.

The green swinging windows too are fitted with spiral Springs. When the wind is weak the green swinging windows are in vertical position but as the wind gets stronger and stronger and the sails start to push the green swinging windows the increased force will push the spiral springs. This will cause the green swinging windows to shift out of plane and consequently permit some of the air to pass freely through the slowly widening gap. As the wind gets stronger the gap will get wider allowing more air to pass through it. The BSW will produce power in slow and fast wind, without making noise.

Given the two salient characteristics of the BSW, massive size and slow motion, it is unfathomable that this turbine will result in killing birds

**The****Blinking sail windmill**does not need a prototype to prove its magical capability since the sails which move boats and ships is the proto type for this invention.**This windmill has one of the sales blocking the wind all the time. Therefore it generates power. While all the other sails letting the wind to pass through freely without any obstruction, so as if they do not exist. The result is one sail like in the ship generating power capable of moving a big electrical generator or a big water pump.**

**The sail boats race which takes place every year where the boats travel around the world and all the power is supplied to these boats for this very long trip comes from a piece of cloth its price equivalent to some gallons of petrol. If changed to an engine boat it will need tons and tons of petrol to complete the journey around the world besides the spare parts and the initial high cost.**

**When you watch these boats you can really see them moving at a high speed and cutting through the water with real force and big power and all of this is coming from a peace of cloth practically worth's nothing.**

**If we make the electrical generator of the Blinking Sail Windmill having multi coil so when the wind is week only one coil activated then when the wind gets faster the second coil is activated so we get more electrical power and if the wind gets stronger the third coil activated and so on.**

**when the wind gets much stronger the spiral spring of the horizontal bars starts to act so the horizontal bars start to swing to the other side, so even the active sail ( the sail which is blocking the wind) starts to let some of the wind to pass through the active sail so the wind do not damage the sail and as the wind gets stronger the gap gets bigger, therefore all the time the Blinking Sail Windmill is safe and generates electricity at the strongest winds besides generating electricity at the weakest wind near to stand still speed.**

**Jasim Al-azzawi**

**Sail windmill tower design**

**https://www.youtube.com/watch?v=iyXvMq8-Ppk&feature=youtu.be**

**Sail windmill helical design**

**https://www.youtube.com/watch?v=UzkON0mTeNk&feature=youtu.be**

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